如何替换php中的现有图像

时间:2019-03-10 10:00:23

标签: php image replace upload

如何使用php替换文件夹中的现有图像? 当我单击上载按钮时,图像只是添加到我的文件夹中,而不是替换它。能否请您添加或重新排列我的代码。预先感谢。

<?php
$target_dir = "uploads/";
$target_file = $target_dir . basename($_FILES["fileToUpload"]["name"]);
$uploadOk = 1;
$imageFileType = strtolower(pathinfo($target_file,PATHINFO_EXTENSION));
// Check if image file is a actual image or fake image
if(isset($_POST["submit"])) {
$check = getimagesize($_FILES["fileToUpload"]["tmp_name"]);
if($check !== false) {
    echo "File is an image - " . $check["mime"] . ".";
    $uploadOk = 1;
} else {
    echo "File is not an image.";
    $uploadOk = 0;
}
}
// Check if file already exists
if (file_exists($target_file)) {
echo "Sorry, file already exists.";
$uploadOk = 0;
}
// Check file size
if ($_FILES["fileToUpload"]["size"] > 500000000000) {
echo "Sorry, your file is too large.";
$uploadOk = 0;
}
// Allow certain file formats
if($imageFileType != "jpg" && $imageFileType != "png" && $imageFileType 
!= 
"jpeg"
&& $imageFileType != "gif" ) {
echo "Sorry, only JPG, JPEG, PNG & GIF files are allowed.";
$uploadOk = 0;
}
// Check if $uploadOk is set to 0 by an error
if ($uploadOk == 0) {
echo "Sorry, your file was not uploaded.";
// if everything is ok, try to upload file
} else {
if (move_uploaded_file($_FILES["fileToUpload"]["tmp_name"], 
$target_file)) {

    echo "The file ". basename( $_FILES["fileToUpload"]["name"]). " has 
been uploaded.";
} else {
    echo "Sorry, there was an error uploading your file.";
}
}
?>

2 个答案:

答案 0 :(得分:1)

当前您的代码可以,它只是将图像添加到您的文件夹中,并且图像名称与您的文件名相同。

正如我在代码中签入一样,您已添加了现有文件的条件,这意味着如果您上传的名称相同,则它会向您发送错误消息。

因此,只需在下面的代码中注释并尝试运行即可。

// Check if file already exists
if (file_exists($target_file)) {
echo "Sorry, file already exists.";
$uploadOk = 0;
}

答案 1 :(得分:0)

只需注释或删除这段代码:

来自

// Check if file already exists
if (file_exists($target_file)) {
echo "Sorry, file already exists.";
$uploadOk = 0;
}

// Check if file already exists
// if (file_exists($target_file)) {
// echo "Sorry, file already exists.";
// $uploadOk = 0;
// }

或将其从您的代码中删除...