Question

我正在尝试从带有Lumen响应的单元测试中获取响应内容作为字符串：

class MovieQueryTest extends TestCase
{
    use DatabaseMigrations;

    public function testCanSearch()
    {
        Movie::create([
            'name' => 'Fast & Furious 8',
            'alias' => 'Fast and Furious 8',
            'year' => 2016
        ]);

        $response = $this->post('/graphql', [
            'query' => '{movies(search: "Fast & Furious"){data{name}}}'
        ]);

        $response->getContent(); // Error: Call to undefined method MovieQueryTest::getContent()
        $response->getOriginalContent(); // Error: Call to undefined method MovieQueryTest::getOriginalContent()
        $response->content; // ErrorException: Undefined property: MovieQueryTest::$content
    }
}

但是我无法弄清楚如何获得响应内容。

我不想使用流明TestCase->seeJson()方法。

我只需要获取响应内容。

Answer 1

$response还包含一个response字段，您需要在该字段上调用getContent()，因此您首先需要提取该字段，然后调用getContent()，因此在代码中这将变成：

public function testCanSearch()
    {
        Movie::create([
            'name' => 'Fast & Furious 8',
            'alias' => 'Fast and Furious 8',
            'year' => 2016
        ]);

        $response = $this->post('/graphql', [
            'query' => '{movies(search: "Fast & Furious"){data{name}}}'
        ]);

        $extractedResponse = $response->response; // Extract the response object
        $responseContent = $extractedResponse->getContent(); // Extract the content from the response object

        $responseContent = $response->response->getContent(); // Alternative one-liner

}

如何获得流明响应内容作为字符串？

1 个答案: