Question

import time

class curtime:

    timeu = time.asctime(time.localtime(time.time())) 
    timelist = timeu.split()
    day = timelist[0]
    month = timelist[1]
    date = timelist[2]
    time = timelist[3]
    year = timelist[4]

    def __init__():
        timeu = time.asctime(time.localtime(time.time())) 
        timelist = timeu.split()
        day = timelist[0]
        month = timelist[1]
        date = timelist[2]
        time = timelist[3]
        year = timelist[4]

    def year(self):
        print([self.year])
        return [self.year]

t1 = curtime()
years = t1.year()
print(years)    # this is giving output as [<bound method curtime.year of <__main__.curtime object at 0x00000285753E8470>>]

我希望year(self)函数返回year变量的值，但它返回

> [<bound method curtime.year of <__main__.curtime object at
> 0x00000285753E8470>>]

有什么想法可以实现吗？另外，如果该值可以作为整数返回，那将是很好的。

Answer 1

您实际上离将其付诸实践不远！

您现在遇到的问题是，名称year作为类属性（此行：year = timelist[4]）与方法名称（此行：{{1}）之间存在冲突}。

您可以将代码更新为以下内容：

def year(self):

您将正确获得以下输出：import time class curtime: def __init__(self): timeu = time.asctime(time.localtime(time.time())) timelist = timeu.split() self._day = timelist[0] self._month = timelist[1] self._date = timelist[2] self._time = timelist[3] self._year = timelist[4] def year(self): return [self._year] t1 = curtime() years = t1.year() print(years)

请注意，在这里，我删除了所有类变量，并修复了['2019']实现，以便每个实例都有自己的当前时间。至关重要的一点是，我将__init__用作存储的私有值的属性名称，并将_year用作要使用的函数。

如何使用return语句在python中返回类的变量？

1 个答案: