Question

我有以下代码：

var arrayAxios = [];
            
const array = async() => {
  await sleep(3000);
  _.forEach(tasks, task => {
    let res = _.includes("selected", task.value);
    if (res) {
      this.axios
        .get(url, { params: { data1 } })
        .then(response => {
          arrayAxios.push(this.axios.post(url, { dataAAA }));
        });
    }
  });
};
              
var promises = async() => {
  const arrayAxios = await array();
  await Promise.all(arrayAxios)
    .then(response => {
      resetAll_dataAAA();   // <--- my dataAAA in arrayAxios are reset before post in Promise.all!
    })
    .catch(error => {
      console.log(error);
    });
};

promises();

在将数据发布到DDBB中之前，将执行函数“ resetAll_data（）”。我找不到问题。

有什么建议吗？

非常感谢您！

Answer 1

您正在寻找

async function array() {
  await sleep(3000);
  var arrayAxios = []; // declare the array locally
  _.forEach(tasks, task => {
    let res = _.includes("selected", task.value);
    if (res) {
      arrayAxios.push(this.axios
//    ^^^^^^^^^^^^^^^ push to the array immediately, not asynchronously
        .get(url, { params: { data1 } })
        .then(response => {
          return this.axios.post(url, { dataAAA }));
//        ^^^^^^ chain the promises
        })
      );
    }
  });
  return arrayAxios;
//^^^^^^ give the result to the caller
}

Answer 2

我已经简化了您的示例，因此希望您可以了解正在发生的事情：）

您需要从一个数组中返回一个promise数组，以便能够使用Promise.all来解决它们。

使用await Promise.all().then，使用await或then

毫无意义。

数组从不返回请求承诺，因此在等待时将立即解决

我不相信睡眠也是节点中的功能。

任何问题都让我知道很乐意为您提供帮助。

const axios = {
  get: async(task) => {
    return task.res;
  },
  post: async(task) => {
    return task;
  }
}

const tasks = [{url: 'getting', res: {got: 'got the thing', post: 'thing to post'}}, {url: 'getting 2', res: {got: 'got the thing 2', post: 'thing to post 2'}}]

const getRequest = async(url = '') => { 
  const res = await axios.get(url)
  console.log(res.got)
  return postRequest(res.post)
}

const postRequest = async (url = '') => {
  const res = await axios.post(url)
  console.log(res)
  return res;
}

const array = async() => {
  const createRequests = async task => {
    return getRequest(task)
  }

  return tasks.map(createRequests).filter(Boolean);
};

const promises = async() => {
  console.log('waiting')
  const res = await array()
  const all = await Promise.all(res)
  console.log('awaited')
  console.log('can call your reset')
};

promises();

等待不等待的JavaScript

2 个答案: