Question

我的控制器中有以下代码：

文件：app / controllers / photos_controller.rb

def show_snapshot_comments
    snapshot = Snapshot.find(params[:id])
    @photo = snapshot.photo
    comments = snapshot.comments.paginate :page => params[:page]
    @snapshot_comment = snapshot.comments.new
      respond_to do |format|
        format.js
      end
   end

JavaScript（jQuery）：文件：app / views / photos / show_snapshot_comments.js.erb

$j('#info').append("<%= escape_javascript(render :partial  => "snapshot_comments",
        :locals   => {:snapshot => snapshot, :comments => comments}) %>" );

show_snapshot_copmments从以下位置调用：应用程序/视图/照片/ show.html.erb

它似乎不起作用。

我的错误：

渲染照片/ show_snapshot_comments

ActionView::TemplateError (undefined local variable or method `snapshot' for #<ActionView::Base:0x2aaaaea473c8>) on line #2 of app/views/photos/show_snapshot_comments.js.erb:
1: $j('#info').append("<%= escape_javascript(render :partial  => "snapshot_comments",
2:         :locals   => {:snapshot => snapshot, :comments => comments}) %>" );

    app/views/photos/show_snapshot_comments.js.erb:2
    app/controllers/photos_controller.rb:227:in `show_snapshot_comments'

可能会发生什么想法？

Answer 1

您正尝试将局部变量传递给部分'snapshot_comments'。但是这两个局部变量，快照和注释未在当前范围中定义（在视图中）。

如果要将变量传递给控制器中的视图，则必须执行以下操作：

def show_snapshot_comments
    @snapshot = Snapshot.find(params[:id])
    @photo = snapshot.photo
    @comments = snapshot.comments.paginate :page => params[:page]
    @snapshot_comment = snapshot.comments.new
      respond_to do |format|
        format.js
      end
   end

$j('#info').append("<%= escape_javascript(render :partial  => "snapshot_comments",
        :locals   => {:snapshot => @snapshot, :comments => @comments}) %>" );

尝试上面的代码，看看它是否有效。我只是将快照和评论更改为@snapshot和@comments。

Answer 2

快照在控制器中设置为本地变量，因此模板看不到它。将其设置为实例变量：

@snapshot = Snapshot.find(params[:id])

然后在模板中：

:locals   => {:snapshot => @snapshot

Rails错误通过Javascript提交部分

2 个答案: