Question

考虑此数组：

$userBookmarks = [
    [
        "id": 10000,
        "dateAdded": 1552127606
    ],
    [
        "id": 20000,
        "dateAdded": 1552127610
    ],
    [
        "id": 30000,
        "dateAdded": 1552127614
    ]
]

假设我知道ID为10000，并且要删除id值为10000的子数组，最有效的方法是删除整个子数组并保留以下内容：

$userBookmarks = [
    [
        "id": 20000,
        "dateAdded": 1552127610
    ],
    [
        "id": 30000,
        "dateAdded": 1552127614
    ]
]

我的“最近”尝试：

for( $i = 0; $i < count( $userBookmarks ); $i++ ) {

    $currentBookmark = $userBookmarks[ $i ]; 

    if( $currentBookmark['id'] == $newBookmarkID ) {
        unset( $currentBookmark ); 
        break; 
    } else {
        $userBookmarks[] = $newBookmark; 
    }

}

但实际上什么也没做...

Answer 1

一个简单的解决方法。

您需要unset()对子数组的原始引用。

更改：

unset( $currentBookmark );

收件人：

unset( $userBookmarks[ $i ] );

“功能性”替代方案如下所示：

$userBookmarks = [
    ["id" => 10000, "dateAdded" => 1552127606],
    ["id" => 20000, "dateAdded" => 1552127610],
    ["id" => 30000, "dateAdded" => 1552127614]
];

$newBookmarkID = 10000;

$userBookmarks = array_filter($userBookmarks, function ($v) use ($newBookmarkID) {
        return $v['id'] != $newBookmarkID;
    });

var_export($userBookmarks);

演示：https://3v4l.org/uhDB2

从多维数组中删除数组的最有效方法

1 个答案: