Question

//存储的过程名称：insertName，_id是自动递增

try { 

        $sql = "CALL insertName(:_id, :_name)";
        $res = $pdo->prepare($sql);
        $res -> bindValue(":_id","NULL");
        $res -> bindValue(":_name",$name);
        $res->execute(); 
        $res->setFetchMode(PDO::FETCH_ASSOC);
} catch( PDOException $e ) {

        die( "ERROR ..." .$e->getMessage());
}

//如果我尝试直接插入数字，一切正常

try {  
        $sql = "CALL insertName(:_id, :_name)";

        $res = $pdo->prepare($sql);
        $res -> bindValue(":_id",1);
        $res -> bindValue(":_name",$name);
        $res->execute(); 
        $res->setFetchMode(PDO::FETCH_ASSOC);
} catch( PDOException $e ) {

        die( "ERROR ..." .$e->getMessage());
}

//即使我不使用存储过程就尝试了

try {  
        $sql = 'INSERT INTO (id,name) VALUES (NULL,"'.$name.'" )';
        $res = $pdo->prepare($sql);
        $res->execute(); 
} catch( PDOException $e ) {

        die( "ERROR ..." .$e->getMessage());
}

Answer 1

仅插入名称值，因为id是自动递增的，所以它将自动获取值

Answer 2

您应将变量NULL设置为字符串，然后将其传递给bindValue：

try { 
        $id = "NULL"
        $sql = "CALL insertName(:_id, :_name)";
        $res = $pdo->prepare($sql);
        $res -> bindValue(":_id", $id);

您必须确保可以将NULL保存为该列的值！

Answer 3

//I changed the stored procedure

开始交易；

DELIMITER |

创建过程insertName（_name）

BEGIN

//operations

INSERT INTO TABLE VALUES (NULL,_name);

END;

| DELIMITER;

提交；

//and then i call insertName(_name)

主键错误（自动递增int）在php中调用存储过程

3 个答案: