Question

在PHP网站上的example之后，我能够编写一个简单的脚本并将其放在服务器上，然后通过命令<link rel="stylesheet" href="https://maxcdn.bootstrapcdn.com/bootstrap/4.0.0/css/bootstrap.min.css" integrity="sha384-Gn5384xqQ1aoWXA+058RXPxPg6fy4IWvTNh0E263XmFcJlSAwiGgFAW/dAiS6JXm" crossorigin="anonymous"> <div class="container"> <div class="row"> <div class="col-2 col-sm-1 col-md-1 col-lg-2"> <div> <a>Some codes</a> </div> </div> <div class="col-8 col-sm-9 col-md-9 col-lg-8"> <div> <nav> <ul class="cf--main-menu-wrapper"> <li><a href="#">Home</a></li> <li><a href="#">Pricing</a></li> <li><a href="#">Our Features</a></li> </ul> </nav> </div> </div> <div class="col-2 col-sm-2 col-md-2 col-lg-2"> <div> <a>Download App</a> </div> </div> </div> </div>连接到它。 PHP代码是：

telnet example.com 10000

当我连接telnet时，它运行良好。无论在终端机中键入什么内容，我都会被发回。但是

但是，我无法通过JavaScript连接到它。我在MDN中使用的代码如下：

#!/usr/local/bin/php -q
<?php
error_reporting(E_ALL);

/* Allow the script to hang around waiting for connections. */
set_time_limit(0);

/* Turn on implicit output flushing so we see what we're getting
 * as it comes in. */
ob_implicit_flush();

$address = '<server-ip-address>';
$port = 10000;

if (($sock = socket_create(AF_INET, SOCK_STREAM, SOL_TCP)) === false) {
    echo "socket_create() failed: reason: " . socket_strerror(socket_last_error()) . "\n";
}

if (socket_bind($sock, $address, $port) === false) {
    echo "socket_bind() failed: reason: " . socket_strerror(socket_last_error($sock)) . "\n";
}

if (socket_listen($sock, 5) === false) {
    echo "socket_listen() failed: reason: " . socket_strerror(socket_last_error($sock)) . "\n";
}

do {
    if (($msgsock = socket_accept($sock)) === false) {
        echo "socket_accept() failed: reason: " . socket_strerror(socket_last_error($sock)) . "\n";
        break;
    }
    /* Send instructions. */
    $msg = "\nWelcome to the PHP Test Server. \n" .
        "To quit, type 'quit'. To shut down the server type 'shutdown'.\n";
    socket_write($msgsock, $msg, strlen($msg));

    do {
        if (false === ($buf = socket_read($msgsock, 2048, PHP_NORMAL_READ))) {
            echo "socket_read() failed: reason: " . socket_strerror(socket_last_error($msgsock)) . "\n";
            break 2;
        }
        if (!$buf = trim($buf)) {
            continue;
        }
        if ($buf == 'quit') {
            break;
        }
        if ($buf == 'shutdown') {
            socket_close($msgsock);
            break 2;
        }
        $talkback = "PHP: You said '$buf'.\n";
        socket_write($msgsock, $talkback, strlen($talkback));
        echo "$buf\n";
    } while (true);
    socket_close($msgsock);
} while (true);

socket_close($sock);
?>

在Firefox控制台中的结果是：

var exampleSocket = new WebSocket("wss://example.com:10000");

我还尝试了undefined Firefox can’t establish a connection to the server at wss://example.com:10000/.版本。我收到错误“无法建立与服务器的安全连接”。请注意，我已经在网站上启用了ssl，因此我认为它应该能够安全地连接。
有什么想法可以使用JavaScript连接到上面的PHP代码吗？

无法通过JavaScript连接到PHP套接字

0 个答案: