Question

我正在用Python创建一个模拟乘法闪存卡的程序。我已经走了很远，但是我不知道如何不重复数字的组合。如何检查是否已经显示了一对数字？

from __future__ import division
from itertools import combinations
import random
amountCorrect = 0
amountMissed = 0
comb = combinations([1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12], 2)

print("Type 0 at any time to exit and see your score.")
while True:
  firstNumber = random.randint(1,12)
  secondNumber = random.randint(1,12)
  ans = int(input("What is " + str(firstNumber) + " x " + str(secondNumber) + ": "))
  if ans == 0:
    break
  elif ans == firstNumber * secondNumber:
    amountCorrect += 1
  else:
    amountMissed += 1

totalProblems = amountCorrect + amountMissed
percentCorrect = amountCorrect/totalProblems

if .9 < percentCorrect <= 1:
  print("Great job, you are doing awesome!")
elif .7 <= percentCorrect <= .89:
  print("You are doing well,keep it up.")
elif .5 <= percentCorrect <= .69:
  print("You are half way to becoming a master.")
else:
  print("Keeping practicing, you will be a master one day.")

Answer 1

简而言之，使用一组存储已使用的数字对。这是一些代码。您永远不会在代码中使用combinations，因此我将其删除。

from __future__ import division
import random
amountCorrect = 0
amountMissed = 0
highestNumber = 12

print("Type 0 at any time to exit and see your score.")
used = set()
while True:
  if len(used) == highestNumber ** 2:
      break
  while True:
    firstNumber = random.randint(1,highestNumber)
    secondNumber = random.randint(1,highestNumber)
    pair = (firstNumber, secondNumber)
    if pair not in used:
      used.add(pair)
      break
  ans = int(input("What is " + str(firstNumber) + " x " + str(secondNumber) + ": "))
  if ans == 0:
    break
  elif ans == firstNumber * secondNumber:
    amountCorrect += 1
  else:
    amountMissed += 1

totalProblems = amountCorrect + amountMissed
percentCorrect = amountCorrect/totalProblems

if .9 < percentCorrect <= 1:
  print("Great job, you are doing awesome!")
elif .7 <= percentCorrect <= .89:
  print("You are doing well,keep it up.")
elif .5 <= percentCorrect <= .69:
  print("You are half way to becoming a master.")
else:
  print("Keeping practicing, you will be a master one day.")

我刚刚创建了一个名为used的空集，并添加了一个新的内部循环。该循环测试是否已使用该对数字。如果是这样，它将再次循环并尝试新的一对数字。我还添加了一个变量以存储尽可能多的数字，并且used集的测试已满。如果测验已满，我结束测验。没有这个，当尝试所有可能性时，程序将进入无限循环。

请注意，此代码将同时允许1,2和2,1。如果只允许其中之一，请将(firstNumber, secondNumber)和(secondNumber, firstNumber)都添加到used集中。

检查是否在组合列表中找到数字组合

1 个答案: