下面的代码可以完美地在字符串(大规模.txt文件)中创建单词出现的CSV列表,就像这样:
Name;Total
THE;23562
OF;15954
AND;15318
IN;12159
TO;11879
A;11145
I;6135
WAS;6045
etc...
我现在想要的是两个单词对,如果足够容易的话甚至三个单词对。所以像
Name;Total
OF THE;25
FROM THE;20
BY WHICH;13
OF WHICH;5
etc...
如何修改现有代码以检查配对而不是单个单词?
//chrisjopa.com/2016/04/21/counting-word-frequencies-with-javascript/
var fs = require('fs');
var file = 'INPUT.txt';
//Create Headers for the CSV File
const createCsvWriter = require('csv-writer').createObjectCsvWriter;
const csvWriter = createCsvWriter({
//Define Pathname to your choice
path: 'Data1.csv',
header: [
{id: 'name', title: 'Name'},
{id: 'total', title: 'Total'},
]
});
// read file from current directory
fs.readFile(file, 'utf8', function (err, data) {
if (err) throw err;
var wordsArray = splitByWords(data);
var wordsMap = createWordMap(wordsArray);
var finalWordsArray = sortByCount(wordsMap);
//Write CSV Output File
csvWriter
.writeRecords(finalWordsArray)
.then(()=> console.log('DONE'));
});
function splitByWords (text) {
// Removes all special characters, then white spaces,
//then converts to all capital letters, then splits the words
var noPunctuation = text.replace(/[\.,-\/#!$%\^&\*;:{}�=\-_'`’~"()@\+\?><\[\]\+]/g, '');
var noExtraSpaces = noPunctuation.replace(/\s{2,}/g," ");
var allUpperCase = noExtraSpaces.toUpperCase();
var wordsArray = allUpperCase.split(/\s+/);
return wordsArray;
}
//This is the part in the code that I feel is the place to check for word
//pairs, but I'm not sure how I'm supposed to write it.
function createWordMap (wordsArray, ) {
// create map for word counts
var wordsMap = {};
wordsArray.forEach(function (key) {
if (wordsMap.hasOwnProperty(key)) {
wordsMap[key]++;
} else {
wordsMap[key] = 1;
}
});
return wordsMap;
}
function sortByCount (wordsMap) {
// sort by count in descending order
var finalWordsArray = [];
finalWordsArray = Object.keys(wordsMap).map(function(key) {
return {
name: key,
total: wordsMap[key]
};
});
finalWordsArray.sort(function(a, b) {
return b.total - a.total;
});
return finalWordsArray;
}
答案 0 :(得分:0)
从wordsArray
,创建另一个将每对单词组合在一起的数组。例如,来自{p的wordsArray
['Foo', 'Bar', 'Baz', 'Buzz']
创建:
['Foo Bar', 'Bar Baz', 'Baz Buzz']
然后,您可以使用已经完全计数每对出现次数的完全相同的功能-只需使用createWordMap
对其进行调用(然后调用sortByCount
)。例如:
const wordsArray = ['Foo', 'Bar', 'Baz', 'Buzz', 'Foo', 'Bar'];
const wordPairsArray = [];
for (let i = 1; i < wordsArray.length; i++) {
wordPairsArray.push(wordsArray[i - 1] + ' ' + wordsArray[i]);
}
const wordPairMap = createWordMap(wordPairsArray);
const wordPairCount = sortByCount(wordPairMap);
console.log(wordPairCount);
// the following is your original code:
function createWordMap(wordsArray, ) {
// create map for word counts
var wordsMap = {};
wordsArray.forEach(function(key) {
if (wordsMap.hasOwnProperty(key)) {
wordsMap[key]++;
} else {
wordsMap[key] = 1;
}
});
return wordsMap;
}
function sortByCount(wordsMap) {
// sort by count in descending order
var finalWordsArray = [];
finalWordsArray = Object.keys(wordsMap).map(function(key) {
return {
name: key,
total: wordsMap[key]
};
});
finalWordsArray.sort(function(a, b) {
return b.total - a.total;
});
return finalWordsArray;
}
要将其扩展到不仅仅是对,只需更改循环以将动态数量的元素连接在一起即可。
function combineWords(words, wordsInItem) {
const items = [];
for (let i = wordsInItem - 1; i < words.length; i++) {
const start = i - (wordsInItem - 1);
const end = i + 1;
items.push(words.slice(start, end).join(' '));
}
return items;
}
function getCount(words, wordsInItem) {
const combinedWords = combineWords(words, wordsInItem);
const map = createWordMap(combinedWords);
const count = sortByCount(map);
console.log(count);
}
getCount(['Foo', 'Bar', 'Baz', 'Buzz', 'Foo', 'Bar'], 2);
getCount(['Foo', 'Bar', 'Baz', 'Buzz', 'Foo', 'Bar', 'Baz'], 3);
// the following is your original code:
function createWordMap(wordsArray, ) {
// create map for word counts
var wordsMap = {};
wordsArray.forEach(function(key) {
if (wordsMap.hasOwnProperty(key)) {
wordsMap[key]++;
} else {
wordsMap[key] = 1;
}
});
return wordsMap;
}
function sortByCount(wordsMap) {
// sort by count in descending order
var finalWordsArray = [];
finalWordsArray = Object.keys(wordsMap).map(function(key) {
return {
name: key,
total: wordsMap[key]
};
});
finalWordsArray.sort(function(a, b) {
return b.total - a.total;
});
return finalWordsArray;
}