Question

我是Java的新手，正在尝试实现重置功能。这是一款猜数字游戏，猜中正确的数字后，我想通过按重置按钮重置游戏，然后开始新的游戏。

var actualNum = randomNumber();

function randomNumber(){
  return Math.floor(Math.random() * 101);
}

function findCorrectGuess(actualNum,userGuess){
  if(userGuess > actualNum){
    return "That is too high!"
  } else if (userGuess < actualNum){
    return "That is too low!"
  } else if (userGuess === actualNum){
    return "BOOM!"
  }
}

function reset(){
  document.getElementById('input').value = "";
  el = document.getElementById('player-guess')
  el.removeChild(el.firstChild)
}

function clearField(){
  document.getElementById('input').value = "";
}

function guessToUI(){
  let userGuess = document.getElementById('input').value;
  document.getElementById('player-guess').innerHTML = `<center><h1>Your last guess was</h1><h2>${userGuess}</h2><h3>${findCorrectGuess(parseInt(actualNum),parseInt(userGuess))}</h3></center>`
}

function listeners(){
  document.getElementById('guesser').addEventListener('click', guessToUI);
  document.getElementById('clear').addEventListener('click', clearField);
  document.getElementById('reset').addEventListener('click', reset);
}

listeners();

在我猜出正确的数字并单击重置按钮后，似乎由我的randomNumber函数生成的以前的数字仍然保留在新游戏上。谁能帮我解决这个问题？谢谢！

Answer 1

将生成您的随机数的代码放入reset方法中，以便获得新的随机数。

function reset(){
  actualNum = randomNumber();
  document.getElementById('input').value = "";
  el = document.getElementById('player-guess')
  el.removeChild(el.firstChild)
}

重置游戏逻辑

1 个答案: