Question

所以我有多个文件用于执行游戏的不同功能。我遇到问题的文件是我创建的向游戏添加按钮的功能。我将此文件导入另一个需要使用按钮功能的文件，但是当从功能文件中将其明确定义为功能时，该程序崩溃，提示“按钮未定义”。有人知道如何解决这个问题吗？

这是按钮代码：

def Button(Text, X, Y, Width, Height, Inactive_Colour, Active_Colour, Action = None):
    Cursor = pg.mouse.get_pos()

    Click = pg.mouse.get_pressed()

    if X + Width > Cursor[0] > X and Y + Height > Cursor[1] > Y:
        pg.draw.rect(Display, Active_Colour, (X, Y, Width, Height))
        if Click[0] == 1 and Action != None:
            if Action == "Quit":
                pg.quit()
                quit()

            elif Action == "Controls":
                Controls()

            elif Action == "Play":
                Game_Loop()

            elif Action == "Main Menu":
                Main_Menu()

            elif Action == "Objective":
                Objective()

    else:
        pg.draw.rect(Display, Inactive_Colour, (X, Y, Width, Height))
        Text_To_Button(Text, Black, X, Y, Width, Height)

这是使用按钮文件中按钮功能的主菜单代码：

import pygame as pg
from Settings import *
from Buttons import *
from Text import *

def Main_Menu():
    Main_Menu = True
    while Main_Menu:
        for event in pg.event.get():
            if event.type == pg.QUIT:
                pg.quit()
                quit()

            elif event.type == pg.KEYDOWN:
                if event.key == pg.K_RETURN:
                    Main_Menu = False

                elif event.key == pg.K_ESCAPE:
                    pg.quit()
                    quit()

        Display.fill(White)

        Message_To_Screen("RPG", Light_Green, -180, Size = "Large")

#        Message_To_Screen("Press Return to play, P to pause, or Escape to quit.", BLACK, 180, Size = "Small")
        Button("Play", 25, 500, 150, 50, Dark_Green, Light_Green, Action = "Play")
        Button("Controls", 225, 500, 150, 50, Dark_Cyan, Light_Cyan, Action = "Controls")
        Button("Objective", 425, 500, 150, 50, Dark_Yellow, Light_Yellow, Action = "Objective")
        Button("Quit", 625, 500, 150, 50, Dark_Red, Light_Red, Action = "Quit")

        pg.display.update()

        Clock.tick(15)

Main_Menu()

当按钮功能位于同一文件中时，该按钮功能有效，但是当我从其他文件导入该按钮功能时，该按钮功能无效，就像当它存在时一样。

导入文件时功能不起作用

0 个答案: