Question

我有一个字符串，我需要在其中提取前3个数字，并在计算完后再提取3个数字。

代码如下：

let val = pref.string(forKey: "RemoteData")
print(val) //Optional("23,8,21,1,2,16,17,18,11,23,14,6,8,13,4,21,15,22,1,2,9,16,17,7,18,11,32,14,6,33,23,8,31,21,1,3,2,16,24,17,18,5")

我需要做这样的事情：

let startCount = pref.object(forKey: "startCountValue") as? Int ?? 0
let lstCount = pref.object(forKey: "LastCountValue") as? Int ?? 3
let UnlockId = arrayV[startCount..<lstCount]

我在上面对整数数组进行过此操作。但是在这里，我不知道如何从字符串中获取前三个值：

23,8,21我需要这样做let UnlockId = arrayV[startCount..<lstCount]。

一段时间后，我会将startCount增加到+ 3，因此下一次从4增加到6。

问题出在Optional("23,8,21,1,2,16,17,18,11,23,14,6,8,13,4,21,15,22,1,2,9,16,17,7,18,11,32,14,6,33,23,8,31,21,1,3,2,16,24,17,18,5")

我喜欢从0到3的第一个3的方式。我喜欢let UnlockId = arrayV[startCount..<lstCount]。但是在这种情况下，我该如何对我的上述值做同样的事情？

更新的代码：

func collectionView(_ collectionView: UICollectionView, cellForItemAt indexPath: IndexPath) -> UICollectionViewCell {
    let gameId = gameInfo["game_id"] as? String  // its printing correct values
    let val = pref.string(forKey: "RemoteData")!
    let arr = val.components(separatedBy:",")
    let startCount = pref.object(forKey: "startCountValue") as? Int ?? 0
    let lstCount = pref.object(forKey: "LastCountValue") as? Int ?? 3
    let unlockId = arr[startCount..<lstCount]

    if unlockId.contains(gameId!) {
        print("its locked")
    } else {
        print("its  not locked")
    }
}

在此处崩溃：unlockId.contains(gameId!)，但游戏ID未打印。变成零。

Answer 1

您可以尝试

Sub WriteXMLContents2Sheet()
  Const MAXCOLUMNS& = 15                          ' << change to columns limit in xml
  Dim linEscrita As Long: linEscrita = 2          ' << start row

  Application.ScreenUpdating = False
  Dim wsBase     As Worksheet
  Set wsBase = ThisWorkbook.Worksheets("Name of worksheet")
'[1] load xml
  Dim resp       As MSXML2.DOMDocument60
  Dim lista      As IXMLDOMNodeList
  Dim nodeAtual  As IXMLDOMNode
  Dim childNode  As IXMLDOMNode
  Set resp = New DOMDocument60
  resp.LoadXML (FunctionForGettingXMLfromWebService)
'[2] set nodelist to memory (XPath possibly could be refined :-)
  Set lista = resp.SelectNodes("//node1/node2")
'[3] dimension temporary variant (1-based) 2-dim array to hold contents
  ReDim tmp(1 To lista.Length, 1 To MAXCOLUMNS)
' [4] loop thru nodelist
  Dim c&, r&                                            ' declare row/column counters
  r = 1
  For Each nodeAtual In lista
    c = 1
    If nodeAtual.HasChildNodes Then
        For Each childNode In nodeAtual.ChildNodes
            tmp(r, c) = childNode.Text
            c = c + 1                                   ' increment column counter
        Next childNode
        r = r + 1                                       ' << move row counter into If condition to avoid empty lines
    End If
  Next nodeAtual
'[5] write array content to sheet
  wsBase.Range("A" & linEscrita).Resize(UBound(tmp), UBound(tmp, 2)) = tmp

  Application.ScreenUpdating = True
End Sub

Answer 2

尝试一下：

func testeFunc(arrayItens: String) {

    let stringArray = arrayItens.components(separatedBy: ",")

    var arrayTemp = [String]()
    var count = 0

    for item in stringArray {
        if count <= 3 {
            arrayTemp.append(item)
            count += 1
        }else{
            print(arrayTemp)
            arrayTemp.removeAll()
            count = 0
        }
    }
}

同时从字符串获取前三个索引值

2 个答案: