Question

您好，我在这里是不得已的方法。对于此作业，我无法弄清楚某些事情，例如如何将小数显示为整数。例如，.29应该是29.00。我也不知道如何正确显示项目数，就像有2个项目（3个鸡蛋和2个奶酪）一样，我怎么只显示2个项目而不是5个？

我已附上此作业的指导原则以及到目前为止的内容。谢谢您的帮助！

A部分您的程序在启动时应从用户获得以下信息： •收银员的姓名。 •说明商店的所在地（亚利桑那州，纽约等） •日期（分为日，月和年）

B部分该程序应以以下格式向用户显示欢迎消息：

您好（出纳名称）欢迎使用收银应用。您目前正在为（州）的一家商店兑现。今天的日期是（日期）。

该程序应允许用户输入不限数量的产品，产品名称，价格和购买数量。程序必须计算要添加到价格中的税额，具体取决于程序在以下三个州中的哪个州使用：纽约-9.75％新泽西州-8.25％康涅狄格州-7.5％田纳西州-4.5％其他-10％

在计算了单个产品的欠款总额之后，程序应显示产品名称和总额，然后询问用户是否要输入其他产品，即

鸡蛋-$ 10.74

您想输入其他产品吗？用户输入完所有产品后，您应该显示购买摘要，告诉用户输入了多少商品以及应付款总额。您输入了14个产品。您的欠款总额为$ 845.89

#include <iostream>
using namespace std;

int main() {
    string state, month, day, year, cashierName, productName;
    char YorN;
    float price, tax, productTotal, productQuantity, totalQuantity = 0, total = 0;


    cout << "Enter name: ";
    cin >> cashierName;
    cout << "Are you in NY, NJ, CT, TN, or other?: ";
    cin >> state;
    cout << "Enter month: ";
    cin >> month;
    cout << "Enter day: ";
    cin >> day;
    cout << "Enter year: ";
    cin >> year;

    cout << "Hello " << cashierName << ". Welcome to Cashier App.\n";
    cout << "You are currently cashing for a store located in " << state << ".\n";
    cout << "Today's date is " << month << " " << day << ", " << year << ".\n";

    if(state == "NY" || state == "ny") {
        tax = .0975;
    }
    else if (state == "NJ" || state == "nj") {
            tax = .0825;
    }
    else if (state == "CT" || state == "ct") {
            tax = .075;
    }
    else if (state == "TN" || state == "tn") {
            tax = .045;
    }
    else {
        tax = .1;
    }

    cout << "Do you want to add a product to your cart? (Y/N) ";
    cin >> YorN;
    while(YorN == 'Y' || YorN == 'y') {
        cout << "Enter product name: ";
        cin >> productName;
        cout << "Enter price: ";
        cin >> price;
        cout << "Enter quantity: ";
        cin >> productQuantity;

        productTotal = price * productQuantity * tax;
        total = productTotal + total;
        totalQuantity = productQuantity + totalQuantity;

        int nProductTotal = int(productTotal * 100);
        productTotal = ((float)nProductTotal)/100;
        int nTotal = int(total * 100);
        total = ((float)nTotal)/100;

        cout << productName << " - $" << productTotal << endl;

        cout << "Would you like to enter another another product? (Y/N) ";
        cin >> YorN;

    }

    cout << "You have entered " << totalQuantity << " products. Your total amount owed is $" << total << ".\n";

    return 0;
}

Answer 1

要显示不同产品的数量，您可以用它们来计数

...
int totalQuantity(0);
while(YorN == 'Y' || YorN == 'y') {
    ++totalQuantity;
...
    // remove totalQuantity = productQuantity + totalQuantity;
...
}
cout << "You have entered " << totalQuantity << " products. Your total amount owed is $" << total << ".\n";
...

totalQuantity的类型应为int，而不是float，因为您不能购买2.2种不同的产品。可以将值四舍五入到小数点后两位

productTotal = std::round(price * productQuantity * tax * 100)/100;

请避免

这样的c样式强制转换

(float)nTotal

执行此操作的c ++方法是

static_cast<float>(nTotal);

我不明白您对的意思。29应该是29.00 ，但是您可以通过

实现

double a = 100 * .29;

或

int a = std::round(100 * .29);

或

cout << std::setprecision(2) << 0.29 * 100 << '\n';

如何移动小数并显示特定数字？ C ++

1 个答案: