使用Redux更新或修改阵列中的阵列的最佳实践

Question

我想了解最佳实践，以及我更新或修改数组中数组的方式是否正确。

当前，我处于这种状态：

州

props1 : "props1",
props2 : "props2",
props3 : "props3",
buckets : [{
    bucketProps1 : "bucketProps1",
    bucketProps2 : "bucketProps2",
    bucketProps3 : "bucketProps3",
    blocks : [{
        blockProps1 : "blockProps1",
        blockProps2 : "blockProps2",
        blockProps3 : "blockProps3",
        messages : [{
            messageProps1 : "messageProps1",
            messageProps2 : "messageProps2",
            messageProps3 : "messageProps3",
            replies : [{ 
                repliesProps1 : "repliesProps1",
                repliesProps2 : "repliesProps2",
                repliesProps3 : "repliesProps3",
            },
            {...
            }],
        },
        {...
        }],
    },
    {...
    }],
},
{...
}]

我想在replies数组中添加一个答复：

reducer-sequences.js

case SEQUENCES.ADD_REPLY :

let newReplies = action.payload;

return {
...state,
buckets: state.buckets.map((bucket, i) => i === 0 ? {
        ...bucket,
        blocks: bucket.blocks.map((block, i) => i === 0 ? {
            ...block,
            messages: block.messages.map((message, i) => i === 0 ? {
                ...message,
                replies: [...state.buckets[0].blocks[0].messages[0].replies, newReplies]
            } : message)
        } : block)
    } : bucket)
};

有没有比这更好的方法来编辑数组中的数组了？

您是否建议重构此代码？

谢谢！

Answer 1

如果您没有选择将状态规范化为易于处理的结构，则建议使用immer。

import produce from "immer";

...

case SEQUENCES.ADD_REPLY:
  let newReplies = action.payload;
  return produce(state, draft => {
    draft.buckets[0].blocks[0].messages[0].replies.push(newReplies);
  });
};