Question

我期待使用django REST框架构建“ REST的母亲” rest api。因此，我希望将所有关系表示为url。使用Spring Boot相当容易，但是对于Django REST而言却并非如此。如果我错了，请纠正我。

我必须建模：

const express = require('express');
const { introspectSchema, makeRemoteExecutableSchema, ApolloServer } = require('apollo-server-express');
const { HttpLink } = require('apollo-link-http');
const fetch = require('node-fetch');
const { setContext } = require('apollo-link-context');

async function runServer() {
    const httpLink = new HttpLink({ uri: 'http://remote.graphql.server:5555/graphql', fetch });
    const link = setContext((request, prevContext) => {
        if (prevContext.graphqlContext && prevContext.graphqlContext.headers) {
            return {
                headers: {
                    'Authorization': prevContext.graphqlContext.headers.authorization,
                }
            }
        } else {
            return {}
        }
    }).concat(httpLink);

    const schema = await introspectSchema(link);

    const executableSchema = makeRemoteExecutableSchema({
        schema,
        link,
    });

    const server = new ApolloServer({
        schema: executableSchema,
        context: ({ req }) => ({
            headers: req.headers
          }),
    });

    // middleware
    const app = express();
    server.applyMiddleware({ app });

    app.listen({ port: 4000 }, () =>
        console.log(
            ' Server ready at localhost:4000',
        )
    )
}

runServer();

现在，我希望模型关系可以像以下模式一样进行序列化（简而言之，我仅将User模型显示为json）：

class User(AbstractBaseUser):
    username = models.CharField(max_length=25, unique=True)
    email = models.EmailField()
    created_at = models.DateTimeField(auto_now_add=True)

class Group(models.Model):
    admin = models.ForeignKey(User, related_name='groups', on_delete=models.PROTECT)
    shared_user = models.ManyToManyField(User, related_name='shared_groups')
    name = models.CharField(max_length=25)
    description = models.TextField()
    created_at = models.DateField(auto_now=True)

我知道我可以通过将其传递到{ "id":1, "username":"user_1", "email":"user_1@test.de", "created_at":"2019-03-08T08:42:34.766951Z", "_links":{ "self":"http://127.0.0.1:8000/users/1/", "groups":"http://127.0.0.1:8000/users/1/groups" } }来获取self网址，但是我喜欢在fields部分中获取它。我尝试使用_links添加其他信息。但是我不知道生成代表对象的URL。

有人可以帮忙吗？

通过串行器：

serializers.SerializerMethodField

Django rest-framework：类似于模型序列化的Spring Boot

0 个答案: