Question

我有一个分段控制器，可将两个UIViews xib调用到屏幕上。每个视图的长度因内容而异。由于每个视图的内容是不同的。 UIView在滚动视图中设置。

当使用分段控制器选择选定的UIView时，我将其拉到其他UIView的前面。问题是当向下滚动时，较长的视图仍然可见。我不知道如何只让滚动向下到已拉到最前面的UIView的底部。

我在选项卡选择的功能中使用simpleViewX.isHidden或simpleViewY.isHidden玩耍，但这并不能真正解决问题，因为我仍然可以向下滚动到空白处。

class foodinfo: UIViewController {

var counter = Int()

@IBOutlet var tabs: UISegmentedControl!
@IBOutlet var shiftView: UIView!
@IBOutlet var theTitleLable: UILabel!

var simpleViewX: UIView!
var simpleViewY: UIView!

var theTitleArray = ["Title1","Title2","Title3","Title4","Title5","Title6","Title7"]

override func viewDidLoad() {

    //Different subViews for each selection
    if counter == 0 {
        simpleViewX = SimpleVC0().view
        simpleViewY = SimpleVC1().view
        shiftView.addSubview(simpleViewY)
        shiftView.addSubview(simpleViewX)
    }

    if counter == 1 {
        simpleViewX = SimpleVC2().view
        simpleViewY = SimpleVC3().view
        shiftView.addSubview(simpleViewY)
        shiftView.addSubview(simpleViewX)
    }

    if counter == 2 {
        simpleViewX = SimpleVC4().view
        simpleViewY = SimpleVC5().view
        shiftView.addSubview(simpleViewY)
        shiftView.addSubview(simpleViewX)
    }

    if counter == 3 {
        simpleViewX = SimpleVC6().view
        simpleViewY = SimpleVC7().view
        shiftView.addSubview(simpleViewY)
        shiftView.addSubview(simpleViewX)
    }

    if counter == 4 {
        simpleViewX = SimpleVC8().view
        simpleViewY = SimpleVC9().view
        shiftView.addSubview(simpleViewY)
        shiftView.addSubview(simpleViewX)
    }

    if counter == 5 {
        simpleViewX = SimpleVC10().view
        simpleViewY = SimpleVC11().view
        shiftView.addSubview(simpleViewY)
        shiftView.addSubview(simpleViewX)
    }

    if counter == 6 {
        simpleViewX = SimpleVC12().view
        simpleViewY = SimpleVC13().view
        shiftView.addSubview(simpleViewY)
        shiftView.addSubview(simpleViewX)
    }
}


func getTitle() {
    theTitleLable.text = theTitleArray[counter]
}

@IBAction func tabselected(_ sender: Any) {
    switch (sender as AnyObject).selectedSegmentIndex {
    case 0:
        shiftView.bringSubviewToFront(simpleViewX)
        break
    case 1:
        shiftView.bringSubviewToFront(simpleViewY)
        break
    default:
        break
    }
}
}

Answer 1

我假设您在滚动视图中将proc CopyBitmap ; BMP graphics are saved upside-down. ; Read the graphic line by line (200 lines in VGA format), ; displaying the lines from bottom to top. mov ax, 0A000h mov es, ax mov cx,200 PrintBMPLoop: push cx ; di = cx*320, point to the correct screen line mov di,cx shl cx,6 shl di,8 add di,cx ; Read one line mov ah,3fh mov cx,320 mov dx,offset ScrLine int 21h ; Copy one line into video memory cld ; Clear direction flag, for movsb mov cx,320 mov si,offset ScrLine rep movsb ; Copy line to the screen ;rep movsb is same as the following code: ;mov es:di, ds:si ;inc si ;inc di ;dec cx ;... loop until cx=0 pop cx loop PrintBMPLoop ret endp CopyBitmap用作“容器”，并使用加载的shiftView和simpleViewX确定simpleViewY的高度...

不是将简单视图添加为shiftView的子视图，而是使用垂直shiftView作为UIStackView的子视图。将您的简单视图添加为堆栈视图的shiftView。要“切换”可见的视图，请隐藏另一个视图。堆栈视图会根据剩余的可见视图自动变短或变高，并且，通过将arrangedSubviews的高度限制为堆栈视图的高度，您的可滚动高度也会自动设置。

如果这样做的话，就不需要shiftView。

使用分段控制器的重叠UIView问题

1 个答案: