Question

目前，我有一个txt文件，其数据如下所示：

A11
Temperature=20 Weight=120 Speed=65
B13
Temperature=21 Weight=121 Speed=63
F24
Temperature=18 Weight=117 Speed=78
D43
Temperature=16 Weight=151 Speed=42
C32
Temperature=15 Weight=101 Speed=51

我想将值读入单元格数组并将其转换为矩阵。下面是我的代码：

% At first I read the data into a 1 column array

fid=fopen('file.txt');
tline = fgetl(fid);
tlines = cell(0,1);
while ischar(tline)
    tlines{end+1,1} = tline;
    tline = fgetl(fid);
end
fclose(fid);

% Then I check the size of the cell array

CellSize = size(tlines);
DataSize = CellSize(1,1);

% At last I setup a loop and literately read and input the values

Data = cell(0,3);
for i = 1:DataSize  
    Data{end+1,3} = textscan(tlines{i,1},'Temperature=%f Weight=%f Speed=%f');   
end

但是，我有10x3的空单元格数组。

[]  []  *1x3cell*
[]  []  *1x3cell*
[]  []  *1x3cell*
[]  []  *1x3cell*
[]  []  *1x3cell*
[]  []  *1x3cell*
[]  []  *1x3cell*
[]  []  *1x3cell*
[]  []  *1x3cell*
[]  []  *1x3cell*

我知道问题出在将textscan值输入到单元格数组中。您能帮我解决问题吗？另外，如果数据不包含特定格式，我该如何扔空值。

Answer 1

您犯的唯一错误是使用Data索引{}的内容，而不是使用()索引单元格，请参见help。

我修改了脚本的最后一部分：

% At last I setup a loop and literately read and input the values

Data = cell(DataSize, 3);
for i = 1:DataSize  
    Data(i, :) = textscan(tlines{i}, 'Temperature=%f Weight=%f Speed=%f')  
end

给出以下输出：

Data =
{
  [1,1] = [](0x1)
  [2,1] =  20
  [3,1] = [](0x1)
  [4,1] =  21
  [5,1] = [](0x1)
  [6,1] =  18
  [7,1] = [](0x1)
  [8,1] =  16
  [9,1] = [](0x1)
  [10,1] =  15
  [1,2] = [](0x1)
  [2,2] =  120
  [3,2] = [](0x1)
  [4,2] =  121
  [5,2] = [](0x1)
  [6,2] =  117
  [7,2] = [](0x1)
  [8,2] =  151
  [9,2] = [](0x1)
  [10,2] =  101
  [1,3] = [](0x1)
  [2,3] =  65
  [3,3] = [](0x1)
  [4,3] =  63
  [5,3] = [](0x1)
  [6,3] =  78
  [7,3] = [](0x1)
  [8,3] =  42
  [9,3] = [](0x1)
  [10,3] =  51
}

随后您可以执行以下操作：

% Clean up.
for i = DataSize:-1:1
  if (isempty([Data{i, :}]))
    Data(i, :) = [];
  end
end

这样您的输出看起来像这样：

Data =
{
  [1,1] =  20
  [2,1] =  21
  [3,1] =  18
  [4,1] =  16
  [5,1] =  15
  [1,2] =  120
  [2,2] =  121
  [3,2] =  117
  [4,2] =  151
  [5,2] =  101
  [1,3] =  65
  [2,3] =  63
  [3,3] =  78
  [4,3] =  42
  [5,3] =  51
}

如果事先知道大小，请不要执行Data{end+1,3}之类的操作。我也对此做了相应的修改。

Answer 2

如果要保留标题/名称，这并不是很优雅，但是可以使用：

error : undefined method `put' for <AWS::S3::S3Object:bucketname/folder/subfolder/>:AWS::S3::S3Object

将文本扫描中的值有条理地附加到循环中的单元格数组中

2 个答案: