Question

我试图获取处于自动模式但未运行并启动它们的服务，但我想从脚本中忽略的少数服务除外，是否有办法以正确的格式获取所需的输出，如下所示：如图2所示，因为选择字符串输出了我的脚本（如果无法将service.name用作变量）。我正在使用以下命令

Get-CimInstance win32_service -Filter "startmode = 'auto' AND state != 'running' "  | select name, startname, exitcode | Select-String   "gupdate|RemoteRegistry"  -NotMatch

output that i am getting is

but the desired output is

下面是我的脚本

    $Services = Get-CimInstance win32_service -Filter "startmode = 'auto' AND state != 'running' "  | select name, startname, exitcode | Select-String  -Pattern "gupdate|RemoteRegistry" -NotMatch
$ServicesRunning = Get-CimInstance win32_service -Filter "state = 'running'"
if ([string]::IsNullOrEmpty($Services)){
    Write-Output "OK: All services running | ServicesRunning=$($ServicesRunning.Count);0;0;0;0"
    $host.SetShouldExit(0)
}
else{
    $ServicesStopped=""
    ForEach ($Service in $Services){
        Start-Service @($Service.Name) -ErrorAction SilentlyContinue | Out-Null  
        if ($(Get-Service -Name ($Service.Name)).Status -eq "running"){
            $ServicesStopped += "($Service.Name)(Started manually),"
            If ($ExitCode -eq 0){
                $ExitCode = 1
            }
        }
        Else{
            $ServicesStopped += "$($Service.Name)(Stopped),"
            $ExitCode = 2
        }
    }
    If ($ExitCode -eq 2){
        Write-Output "CRITICAL: Service(s) stopped: $($ServicesStopped.TrimEnd(",")) | ServicesRunning=$($ServicesRunning.Count);0;0;0;0"
        $host.SetShouldExit(2)
    }
    Else{
        Write-Output "WARNING: Service(s) stopped: $($ServicesStopped.TrimEnd(",")) | ServicesRunning=$($ServicesRunning.Count);0;0;0;0"
        $host.SetShouldExit(1)
    }
}

Answer 1

Select-String需要一个字符串或字符串列表作为输入。 Select-Object生成自定义对象的列表。将后者插入前者会使后者的输出转换为字符串。显然这不是您想要的。而且，由于您可以直接Get-CimInstance参数-Filter进行所有过滤，因此完全不需要它：

$fltr = "name!='gupdate' AND name!='RemoteRegistry'" + 
        " AND startmode='auto' AND state!='running'"

Get-CimInstance Win32_Service -Filter $fltr |
    Select-Object Name, StartName, ExitCode

选择字符串的输出在输出中有@ {

1 个答案: