Question

我想从数据数组中获取所有名称。有没有不用迭代器的方法吗？

const data = [
    {name: 'Rushabh', age: 22},
    {name: 'Bonny', age: 24}
]

console.log(Object.values(data));

Answer 1

要仅获取一个属性，则需要直接映射此属性。

(my_env)  ..  $ python test.py
Using TensorFlow backend.
Traceback (most recent call last):
  File "test.py", line 10, in <module>
    import keras
  File "/home/ ../my_env/lib/python3.5/site-packages/keras/__init__.py", line 3, in <module>
    from . import utils
  File "/home/ ../my_env/lib/python3.5/site-packages/keras/utils/__init__.py", line 27, in <module>
    from .multi_gpu_utils import multi_gpu_model
  File "/home/ ../my_env/lib/python3.5/site-packages/keras/utils/multi_gpu_utils.py", line 7, in <module>
    from ..layers.merge import concatenate
  File "/home/ ../my_env/lib/python3.5/site-packages/keras/layers/__init__.py", line 4, in <module>
    from ..engine.base_layer import Layer
  File "/home/ ../my_env/lib/python3.5/site-packages/keras/engine/__init__.py", line 8, in <module>
    from .training import Model
  File "/home/ ../my_env/lib/python3.5/site-packages/keras/engine/training.py", line 21, in <module>
    from . import training_arrays
  File "/home/../my_env/lib/python3.5/site-packages/keras/engine/training_arrays.py", line 8, in <module>
    from scipy.sparse import issparse
ImportError: No module named 'scipy.sparse'

Answer 2

使用WebApplicationServiceResponseBuilder并提取@Configuration属性：

Array.map()

Answer 3

如果您使用的是JQuery，请执行以下操作：

const data = [
    {name: 'Rushabh', age: 22},
    {name: 'Bonny', age: 24}
] 
var names = $.map( data, function(item, key) { return item.name; } );
// names : ['Rushabh', 'Bonny']

Javascript获取对象的所有值

3 个答案: