Question

我更新了下面的问题，因为它的复杂性更高...

有关基于类型的SQL分组的问题吗？

我希望能够列出A型的最大值（基于日期-每个CustID），同时列出B型的所有值

从这里开始：

Date          Ref   Type  CustID
2019-03-04    123   A     1
2019-03-05    124   A     1
2019-03-06    125   B     3
2019-03-07    126   B     4
2019-03-08    127   B     5
2019-03-06    128   A     2
2019-03-07    129   A     2
2019-03-08    130   A     2

对此：

Date          Ref   Type CustID
2019-03-05    124   A    1
2019-03-06    125   B    3
2019-03-07    126   B    4 
2019-03-08    127   B    5
2019-03-08    130   A    2

预先感谢：-）

Answer 1

这是您想要的吗？

with a as (
      select top (1) t.*
      from t
      where type = 'A'
      order by ref desc
     )
select a.*
from a
union all
select t.*
from t
where type = 'B';

或者没有union all：

select top (1) with ties t.*
from t
order by (case when type = 'B' then 1
               else row_number() over (partition by type order by ref desc
          end);

Answer 2

全部使用联盟

select date,ref,type from table where type='B'
union all
select date,ref,type from table where type='A' 
and date = (select max(date) from table where type='A')

Answer 3

尝试使用union all

select top 1 date,ref, type from tablename
where Type='A' order by date desc
union all
select date,ref, type from tablename
where type='B'

Answer 4

以下查询为您提供了类型为A的记录，其中包含最新日期和B记录

  Select * from
   ( SELECT  Date, Ref, Type 
     FROM TABLE
    WHERE TYPE='A' GROUP BY TYPE
    HAVING DATE =MAX(DATE)
     UNION
    SELECT  Date, Ref, Type FROM TABLE
     WHERE TYPE='B'
          )

SQL-组取决于类型

4 个答案: