Question

我应该如何在同一正文中发送文本格式和html格式的电子邮件？ MIMEmultipart的用途是什么？

MIMEMultipart([MIMEText(msg, 'text'),MIMEtext(html,'html')])

我可以使用它接收一封电子邮件，但正文为空

PS：我正在尝试发送文本并在同一正文中附加表格。我不想发送表格作为附件。

html = """
  <html>
   <head>
    <style> 
     table, th, td {{ border: 1px solid black; border-collapse: collapse; }} th, td {{ padding: 5px; }}
    </style>
   </head>
   <body><p>Hello, Friend This data is from a data frame.</p>
    <p>Here is your data:</p>
    {table}
    <p>Regards,</p>
    <p>Me</p>
   </body>
  </html> """

text = """
Hello, Friend.

Here is your data:

{table}

Regards,

Me"""
text = text.format(table=tabulate(df, headers=list(df.columns), tablefmt="grid"))
html = html.format(table=tabulate(df, headers=list(df.columns), tablefmt="html"))
if(df['date'][0].year==1900 and df['date'][0].month==datetime.date.today().month and df['date'][0].day==datetime.date.today().day):
a2=smtplib.SMTP(host='smtp-mail.outlook.com', port=587)
a2.starttls()
myadd='abc@gmail.com'
passwd=getpass.getpass(prompt='Password: ')
try :

    a2.login(myadd,passwd)
except Exception :
    print("login unsuccessful")
def get_contacts(filename):
    name=[]
    email=[]
    with open('email.txt','r') as fl:
         l=fl.readlines()
         print(l)
         print(type(l))
         for i in l:
          try: 
              name.append(i.split('\n')[0].split()[0])
              email.append(i.split('\n')[0].split()[1]) 
          except Exception:
              break
         fl.close()
    return (name,email)
def temp_message(filename):
    with open(filename,'r') as fl1:
        l2=fl1.read()
    return(Template(l2))
name,email=get_contacts('email.txt')    
tmp1=temp_message('temp1.txt')   
for name,eml in zip(name,email):
    msg=MIMEMultipart([MIMEText(msg, 'text'),MIMEtext(html,'html')])
    message=tmp1.substitute(USER_NAME=name.title())
    print(message)
    msg['FROM']=myadd
    msg['TO']=eml
    msg['Subject']="This is TEST"
    msg.attach(MIMEText(message, 'plain')) 
    #       msg.set_payload([MIMEText(message, 'plain'),MIMEText(html, 'html')])
    # send the message via the server set up earlier.
    a2.send_message(msg)
    del msg
    a2.quit()

Answer 1

您需要将消息创建为

def assignment():
  x = input('Type anything')
  random_list = []
  while x != '':
    x = input("Type anything")
    random_list.append(x)
    print(random_list)
  x=x+1
  for i in random_list:
    if i not in random_list:
      random_list.append(i) 
assignment()

，然后附加两个MIMEText部分。

Traceback (most recent call last):
    File "<stdin>", line 1, in <module>
    File "<stdin>", line 8, in assignment
TypeError: can only concatenate str (not "int") to str

已收到：

import numpy as np
from numpy import gradient
import h5py
import matplotlib.pyplot as plt
from scipy.interpolate import RegularGridInterpolator

f = h5py.File('k.h5', 'r') 
list(f.keys())
dset = f[u'data']
dset.shap
dset.value.shape
dset[0:64, 0:64, 0:64]
x = np.linspace(-160, 160, 64)
y = np.linspace(-160, 160, 64)
z = np.linspace(-160, 160, 64)

my_interpolating_function = RegularGridInterpolator((x, y, z), dset.value)
pts = np.array([100, 5, -10])  
my_interpolating_function(pts)

# Apply gradient function
gradx, grady, gradz = np.gradient(dset.value)
gradx.shape

# To find the gradient at any point
gradx_interpol = RegularGridInterpolator((x, y, z), gradx)
grady_interpol = RegularGridInterpolator((x, y, z), grady)
gradz_interpol = RegularGridInterpolator((x, y, z), gradz)


def get_val_and_grads(pts):
    v1, x1, y1, z1 = my_interpolating_function(pts), gradx_interpol(
        pts), grady_interpol(pts), gradz_interpol(pts)
    return v1, x1, y1, z1


##getting_interpolated_values

k1 = my_interpolating_function(pts)
k_dx = gradx_interpol(pts)
k_dy = grady_interpol(pts)
k_dz = gradz_interpol(pts)

def a_1(x,y,z):

    return  -(adot/a**2)*k1

def a_2(x,y,z):

    return (1/a)*k_dx

经过重做的电子邮件程序包（Python 3.6+）可用于发送相同的消息，如下所示：

MIMEMultiPart('alternative')

输出：

>>> text = 'Hello World'
>>> html = '<p>Hello World</p>'

>>> msg = MIMEMultipart('alternative')
>>> msg['Subject'] = 'Hello'
>>> msg['To'] = 'a@example.com'
>>> msg['From'] = 'b@example.com'

>>> msg.attach(MIMEText(text, 'plain'))
>>> msg.attach(MIMEText(html, 'html'))

>>> s.sendmail('a@example.com', 'b@example.com', msg.as_string())
Traceback (most recent call last):
  File "<stdin>", line 1, in <module>
NameError: name 's' is not defined
>>> s = smtplib.SMTP('localhost:1025')
>>> s.sendmail('a@example.com', 'b@example.com', msg.as_string())

Answer 2

在您的“与”处：

def temp_message(filename): 
   with open(filename,'r') as fl1:
      l2=fl1.read()

将其更改为：

def temp_message(filename):
   filename = temp_message('temp1.txt') #changed tmp1 to filename
   with open(filename, 'w+', encoding='utf-8') as fl1:
      fl1.write(text)
      fl1.write(html)
      fl1.write(regards)

您可以仅拆分文本变量的'regards'部分，以便html（table）可以位于两者之间。我对您的问题很困惑（进行了大量编辑），但是如果我没有记错，您的fl1（tempt1.txt）没有任何数据，则您只能“读取”（r）文本文件，但没有什么都不要写。我还建议您将'tmp1 = temp_message（'temp1.txt'）'放入您的 'def temp_message（filename）'以避免混淆。

用python发送电子邮件（MIMEmultipart）

2 个答案: