Question

public static void enterText(String plaintext ) {
    Scanner in = new Scanner(System.in);
    System.out.print("Enter Plaintext: ");
    plaintext = in.nextLine(); 
    int plaintextLenght = plaintext.length();

    int[] array1 = new int[plaintextLenght]; 
    int[] array2 = new int[plaintextLenght]; 

    StringBuilder quoBinary = new StringBuilder();
    StringBuilder remBinary = new StringBuilder();

    for(int i = 0; i < plaintext.length() ; i++) {   
        char character = plaintext.charAt(i); 
        int ascii = (int) character; 
        array1[i]= ascii / 10; 
        array2[i] = ascii % 10; 

        for(int j = 0; j < 8; j++) {  
            **quoBinary.append((array1 & 128) == 0 ? 0 : 1);  
            array1<<= 1;  
            remBinary.append((array2 & 128) == 0 ? 0 : 1);  
            array2<<= 1;**  
        } 
    }

     System.out.println("Quotient = "+ Arrays.toString(array1));  // Print array for quotients
     System.out.println("Remainder = "+ Arrays.toString(array2)); // Print array for quotients
     System.out.println("Binary QQ " + quoBinary);
     System.out.println("Binary RR " + remBinary);    
}

错误消息：

Bad operand types for binary operator  ‘&’
First type: int[]
Second type: int

我无法按位排列一个具有int的数组。

Answer 1

如果您想转换为ASCII则。遍历字符串

for(int i = 0 ; i < str.length() ; i++){
    char character = str.charAt(i);
    System.out.print((int)character);
}

二进制运算符'＆'的错误操作数类型第一类型：int []第二类型：int

1 个答案: