Question

我正在尝试通过AJAX和PHP进行sql数据库调用，其结果将显示在网页中。 javascript似乎工作正常，并且正在正确将GET请求传递到PHP页面，并且未生成任何错误消息。但是，PHP仅返回部分代码。这显示在网页上，代替了我的数据库内容：

0){ while($row = mysqli_fetch_assoc($result)) { echo "
"; echo $row['home']; echo " vs. "; echo $row['away']; echo "

我的第一个怀疑是PHP中的语法错误，但是经过几次尝试后，我找不到一个（作为新手也无济于事！）。

.js函数：

function calldropdown(gameweek) {
    var gameweek = document.getElementById('gameweek').value
    if (window.XMLHttpRequest) {
        xmlhttp = new XMLHttpRequest();
    } else {
        xmlhttp = new ActiveXObject("Microsoft.XMLHTTP");
    }
    xmlhttp.onreadystatechange = function() {
        if (this.readyState == 4 && this.status == 200) {
            document.getElementById("matches").innerHTML = this.responseText;
        }
    };
    xmlhttp.open("GET","/static/gameweek.php?q="+gameweek,true);
    xmlhttp.send();
}

.php文件（已编辑）：

<?php
$q = intval($_GET['q']);

$servername = "myservername";
$username = "myusername";
$password = "mypassword";
$dbname = "mydbname";

$con = mysqli_connect($servername, $username, $password, $dbname);

if (!$con) {
    die('Could not connect: ' . mysqli_error($con));
}

mysqli_select_db($con,"mydbname");
$sql="SELECT home, away FROM matches WHERE gameweek = '".$q."'";
$result = mysqli_query($con,$sql);

if (mysqli_num_rows($result) > 0){
    while($row = mysqli_fetch_assoc($result)) {
        echo "<p>";
        echo $row['home'];
        echo " vs. ";
        echo $row['away'];
        echo "</p>";
    }
} else {
    echo "error";
}
mysqli_close($con);
?>

有什么想法吗？

AJAX-PHP对SQL调用的错误响应

0 个答案: