Question

我在Windows 10上的Python37中，在tkinter中工作，我编写了一个函数did_file_update，该函数每10秒不断扫描一次桌面，以查看文件“ test.txt”是否已更改。还有一个函数abort_window_call，该函数创建带有红色“ ABORT”按钮的窗口。我正在尝试编写一个脚本，该脚本将对这两个函数进行线程化，并允许我单击“ ABORT”按钮并在按下“ START”按钮并调用did_file_update后终止该脚本。

import os
import time
import threading
import tkinter as tk
from tkinter import messagebox
import tkinter.messagebox as msg
from tkinter import Button, Message, Tk


global path_to_watch
path_to_watch = "C:\\Users\\Desktop"

class App():
    def __init__(self):
        pass

    def abort_window_call(self):
        abort_window = Tk()
        abort_window.title("Would you like to abort?")
        abort_window.geometry('50x90+200+200')
        abort_button = tk.Button(abort_window, text='ABORT', font=('century gothic', 24),
                        bg='red', fg='white', height=1, width=5,
                        relief='raised', command=lambda: abort_window.destroy())
        abort_button.pack(padx=10, pady=5)

        abort_window.mainloop()

    def did_file_update(self):
        statinfo_before = os.stat("C:\\Users\\Desktop\\test.txt")
        statinfo_size_before = statinfo_before.st_size

        while 1:
            time.sleep (10)
            statinfo_after = os.stat("C:\\Users\\Desktop\\test.txt")
            statinfo_size_after = statinfo_after.st_size
            if statinfo_size_after != statinfo_size_before:
                print("Updated: test.txt")
                statinfo_size_before = statinfo_size_after
                break
            else:
                pass

    def main(self):
        master = Tk()
        ws = master.winfo_screenwidth()
        hs = master.winfo_screenheight()
        x = (ws/2) - (180)
        y = (hs/2) - (70)
        master.title("File Update")
        master.geometry('360x140+%d+%d' % (x, y))
        msg = Message(master, text = "FILE UPDATE", width=700)
        msg.config(font=('century gothic', 28))
        msg.grid(row=3, column=0)

        start_button = tk.Button(master, text='START', font=('century gothic', 24),
                        bg='green', fg='white', height=1, width=17,
                        relief='raised', command=self.did_file_update)
        start_button.grid(row=1, column=0, sticky='n', padx=10, pady=5)

        master.mainloop()

app=App()

t = threading.Thread(target = app.abort_window_call)
t1 = threading.Thread(target = app.main)

t.start()
t1.start()

tl; dr 如何使abort_window_call函数终止整个程序，即使在按下“ START”键和函数{{1 }}正在运行？

使用tkinter进行线程处理-如何在函数运行时通过按下按钮来终止脚本？

0 个答案: