Question

原始数据具有“ pool pool_name”，然后是0-n行“ member random_member_ip”，是否可以在bash中提取列表？我尝试了一些有条件的直到累了。我在这里先向您的帮助表示感谢。

     pool string_name_1
     member 172.0.0.1
     member 172.0.1.1
     pool string_name_2
     member 172.2.1.2
     member 172.0.2.2
     pool string_name_3
     member 172.2.1.3
     member 172.3.2.3
     member 172.25.25.3
     member 172.25.40.3
     pool string_name_4
     pool string_name_5
     member 5.5.50.5

预期结果

     string_name_1 172.0.0.1 172.0.1.1
     string_name_2 172.2.1.2 172.0.2.2
     string_name_3 172.2.1.3 172.3.2.3 172.25.25.3 172.25.40.3
     string_name_4 
     string_name_5 5.5.50.5

Answer 1

这会将默认的RS更改为pool，因此现在每个记录都由pool分隔。 gsub()用于从输出中删除member字符串。

awk -v RS='pool' '{$1=$1;gsub(/member/,"")}1' inputfile

string_name_1  172.0.0.1  172.0.1.1
string_name_2  172.2.1.2  172.0.2.2
string_name_3  172.2.1.3  172.3.2.3  172.25.25.3  172.25.40.3
string_name_4
string_name_5  5.5.50.5

Answer 2

使用bash可以编写

unset line
while read -r key value; do
    case $key in
        pool)   [[ $line ]] && echo "$line"; line=$value ;;
        member) line+=" $value" ;;
    esac
done < file
echo "$line"

awk中的相同技术可提高性能：

awk '
    $1 == "pool"   {if (line) print line; line = $2} 
    $1 == "member" {line = line OFS $2} 
    END {print line}
' file

从bash中的原始数据中获取列表，或仅格式化输出list_name后跟列表内容

2 个答案: