Question

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我尝试了elif声明“ if age <= 65：”，但显示语法错误。这在下面的代码中有效。所以我不确定什么是错的或我可以做些什么才能使它正常工作。问题是它不会启动“打印（'这是您的退休人员票。'）”。感谢您的帮助，爱你们所有人。

year_born = input('what year were you born? ')
year = (2019)
age = (year - int(year_born))
if age <= 18:
  if age <= 65:
    print('Here is your pensioners ticket.')
  print('Here is your child's fare ticket.')
else:
  print('here is your ticket.')

Answer 1

该错误很可能是print('Here is your child's fare ticket.')，因为您在使用'时没有转义。可能的解决方案：

print('Here is your child\'s fare ticket.')

或

print("Here is your child's fare ticket.")

我的处理方式：

year_born = input('what year were you born? ')
year = 2019
age = (year - int(year_born))
if age <= 18:
    print('Here is your child\'s fare ticket.')
elif age >= 65:
    print('Here is your old person ticket.')
else:
    print('here is your general adult ticket.')

Answer 2

从逻辑的角度来看，您希望囚犯年龄在65岁以上，孩子在18岁以下。否则，他们会得到一张普通票。如果这是正确的，那么我将使用以下内容：

first_name = input('first name only: ')

if first_name[-1] == 'a':
    print('you won $1000!!')
else:
  print('you did not win $1000')

对于其他要首先检查最后一个字母的代码，然后查看长度是否大于5：

Invoke-Expression

Elif在我尝试时不起作用，而在我的上一个代码中起作用时将不起作用

2 个答案: