在记事本++中的字符后清除数据

Question

如何清理下面文本的最后一部分以仅检索到.xls的数据？

/Artifacts & Supporting Docs/AR.01 - WLCE cohort schema Rel 3.0 final Jan, 3, 2013.xls, 247 KB, 06/11/2013

我只需要这一部分/Artifacts & Supporting Docs/AR.01 - WLCE cohort schema Rel 3.0 final Jan, 3, 2013.xls

我尝试使用下面的命令，但是没有按预期工作。

  

选择正则表达式并环绕。区分大小写

     

查找内容：，[0-9]。*

     

替换为：（保留为空）

Answer 1

尝试查找正则表达式xls,.*$并将其替换为xls。您的正则表达式将匹配任何逗号，后跟数字字符，它太宽了。

Answer 2

• Ctrl + H
• 查找内容：\.\S+\K,.+$
• 替换为：LEAVE EMPTY
• 检查环绕
• 检查正则表达式
• 取消检查. matches newline
• 全部替换

说明：

\.      # a dot
\S+     # 1 or more non spaces
\K      # forget all we've seen until this position
,       # a comma
.+      # 1 or more any character but newline
$       # end of line

给出：

/Artifacts & Supporting Docs/AR.01 - WLCE cohort schema Rel 3.0 final Jan, 3, 2013.xls, 247 KB, 06/11/2013
/Artifacts & Supporting Docs/AR.01 - WLCE cohort schema Rel 3.0 final Jan, 3, 2013.pdf, 247 KB, 06/11/2013
/Artifacts & Supporting Docs/AR.01 - WLCE cohort schema Rel 3.0 final Jan, 3, 2013.csv, 247 KB, 06/11/2013

给定示例的结果

/Artifacts & Supporting Docs/AR.01 - WLCE cohort schema Rel 3.0 final Jan, 3, 2013.xls
/Artifacts & Supporting Docs/AR.01 - WLCE cohort schema Rel 3.0 final Jan, 3, 2013.pdf
/Artifacts & Supporting Docs/AR.01 - WLCE cohort schema Rel 3.0 final Jan, 3, 2013.csv

屏幕截图：