Question

我的服务通常会返回以下内容：

anyType{Acc1=96628; Code=E; OnArr=false; CanArr=true; Username=ANDERSON;}

然后我将其推向对象

details.Username = response.getProperty("Username").toString();

并按我需要的方式工作，直到收到没有用户名值的响应为止，返回如下：

anyType{Acc1=96628; Code=E; OnArr=false; CanArr=true; Username=anyType{};}

当我稍后调用details.Username时，它返回“ anyType {}”（作为字符串），而不是返回任何一个空字符串

你能告诉我我想念什么吗？

为清楚起见，我如何到达response ...

SoapObject request = new SoapObject(NAMESPACE, methodName);

PropertyInfo propertyInfo = new PropertyInfo();
propertyInfo.setName("Details");
propertyInfo.setValue(details);
propertyInfo.setType(details.getClass());
request.addProperty(propertyInfo);

SoapSerializationEnvelope envelope = new SoapSerializationEnvelope(SoapEnvelope.VER11);

envelope.dotNet = true;
envelope.implicitTypes = true;
envelope.setOutputSoapObject(request);
envelope.addMapping(NAMESPACE, "Details", Details.class);

HttpTransportSE httpTransportSE = new HttpTransportSE(URL);
httpTransportSE.call(NAMESPACE + methodName, envelope);

SoapObject response = (SoapObject) envelope.getResponse();

[编辑]

以下似乎可以解决问题；但是，我不太确定为什么还是正确的方法。

details.Username = response.getPrimitivePropertyAsString("Username");

Answer 1

这似乎可以通过

解决

details.Username = response.getPrimitivePropertyAsString("Username");

进入 SoapObject.java ，我也可以看到其背后的含义

/**
 * Get the toString value of a property without chance of throwing an
 * exception. An object can be provided to this method; if the property is
 * not found, this object's string representation will be returned.
 *
 * @param defaultThing
 *            toString of the object to return if the property is not found
 * @return the property toString if it exists; defaultThing toString if the
 *         property does not exist, if the defaultThing is null #EMPTY_STRING
 *         is returned
 */

public String getPropertySafelyAsString(final String namespace,final String name,
                                        final Object defaultThing) {
    Integer i = propertyIndex(namespace,name);
    if (i != null) {
        Object property = getProperty(i.intValue());
        if (property != null) {
            return property.toString();
        } else {
            return EMPTY_STRING;
        }
    } else {
        if (defaultThing != null) {
            return defaultThing.toString();
        } else {
            return EMPTY_STRING;
        }
    }
}

如何正确处理Web服务中的anyType（）？

1 个答案: