Question

我有一本词典，键为“标题”，“作者”，“出版年”，其值是列表：

book_dict= {'Titles': ['Double Play', 'Slow Burn', 'Altman Code'], 'Authors': ['Brown, Dan', 'Hannah, Kristin', 'Neri, Penelope'], 
'Publication Year': [2004, 2003, 2006]}

列表中每个条目的位置彼此对应，因此book_dict['Titles'][0]和book_dict['Authors'][0]是有关同一本书的信息。（注意：这些是书籍和作者的真实名字，但实际上并不对应）

我想创建一个包含这样的字典的列表：

[{"Title":"Double Play","Author":"Brown, Dan", "Publication Year":2004}, 
{"Title":"Slow Burn","Author":"Hannah, Kristin", "Publication Year":2003},
{"Title":"Altman Code","Author":"Neri, Penelope'", "Publication Year":2006}]

到目前为止，我已经尝试过：

for i in range(30):
    for k,v in book_dict.items():
        print({k[i]:v[i]})

但是我得到了这个：

{"Title":"Double Play"}
{"Author":"Brown, Dan"}
{"Publication Year":2004}
{"Title":"Slow Burn"}
{"Author":"Hannah, Kristin"}
{"Publication Year":2003}
{"Title":"Altman Code"}
{"Author":"Neri, Penelope"} 
{"Publication Year":2006}

加上一个IndexError: list index out of range

Answer 1

您将不得不对原始字典的值使用zip的某些变体：

>>> [{'Title': t, 'Author': a, 'Publication Year': y} for t, a, y in zip(book_dict['Titles'], book_dict['Authors'], book_dict['Publication Year'])]
[{'Title': 'Double Play', 'Author': 'Brown, Dan', 'Publication Year': 2004}, 
 {'Title': 'Slow Burn', 'Author': 'Hannah, Kristin', 'Publication Year': 2003}, 
 {'Title': 'Altman Code', 'Author': 'Neri, Penelope', 'P
ublication Year': 2006}]

您可能会使用一些实用程序使其更具可读性：

from  operator import itemgetter

items = itemgetter('Titles', 'Authors', 'Publication Year')
[
    {'Title': t, 'Author': a, 'Publication Year': y} 
    for t, a, y in zip(*items(book_dict))
]
# [{'Title': 'Double Play', 'Author': 'Brown, Dan', 'Publication Year': 2004}, 
#  {'Title': 'Slow Burn', 'Author': 'Hannah, Kristin', 'Publication Year': 2003}, 
#  {'Title': 'Altman Code', 'Author': 'Neri, Penelope', 'Publication Year': 2006}]

Answer 2

一种无需对键进行硬编码的通用方法是，对dict的压缩值进行迭代，并用该zip值压缩dict键，以使用dict构造函数构建子字典：

[dict(zip(book_dict, t)) for t in zip(*book_dict.values())]

这将返回：

[{'Titles': 'Double Play', 'Authors': 'Brown, Dan', 'Publication Year': 2004},
 {'Titles': 'Slow Burn', 'Authors': 'Hannah, Kristin', 'Publication Year': 2003},
 {'Titles': 'Altman Code', 'Authors': 'Neri, Penelope', 'Publication Year': 2006}]

Answer 3

尝试一下：

[{k : book_dict[k][j] for k in book_dict} for j in range(len(book_dict['Titles']))]

输出：

[{'Titles': 'Double Play', 'Authors': 'Brown, Dan', 'Publication Year': 2004}, {'Titles': 'Slow Burn', 'Authors': 'Hannah, Kristin', 'Publication Year': 2003}, {'Titles': 'Altman Code', 'Authors': 'Neri, Penelope', 'Publication Year': 2006}]

Answer 4

您可以使用zip()逐步访问多个列表，例如

result = []
for title, author, year in zip(book_dict['Titles'], book_dict['Authors'],     
book_dict['Publication Year']):
    result.append({'Title': title, 'Author': author, 'Year': year})

print result

遍历列表中的字典值以创建新的字典列表

4 个答案: