Oracle数据库适配器:“ pdo_oci ” MySQL数据库适配器:“ pdo_mysql ”
用于建立JOIN查询的代码:
$db = Zend_Db_Table::getDefaultAdapter();
$db->setFetchMode(Zend_Db::FETCH_OBJ);
$select = $db->select()->from(array(
't1' => $this->_Table1
));
$select = $select->join(array(
't2' => $this->_Table2
), 't1.MENU_ID = t2.SUBMENU_ID',
array(
'MENU_ID',
'SET_REDIRECT_URL',
'SUBMENU_TYPE'
));
$select = $select->order(array(
'MENU_ID',
't2.DISPLAY_ORDER'
));
$select = $select->where('t1.IS_ACTIVE = ?', 'Y');
$result = $db->fetchAll($select);
由Oracle适配器(pdo_oci)生成的查询:
SELECT "t1".*, "t2"."MENU_ID" AS "parent_id", "t2"."SET_REDIRECT_URL", "t2"."SUBMENU_TYPE" FROM "DRP_ADMIN_MENU_MASTER" "t1" INNER JOIN "DRP_ADMIN_MENU_MAPPER" "t2" ON t1.MENU_ID = t2.SUBMENU_ID WHERE (t1.IS_ACTIVE = 'Y') ORDER BY "parent_id" ASC, "t2"."DISPLAY_ORDER" ASC
由Mysql适配器(pdo_mysql)生成的查询:
SELECT `t1`.*, `t2`.`MENU_ID` AS `parent_id`, `t2`.`SET_REDIRECT_URL`, `t2`.`SUBMENU_TYPE` FROM `DRP_ADMIN_MENU_MASTER` AS `t1` INNER JOIN `DRP_ADMIN_MENU_MAPPER` AS `t2` ON t1.MENU_ID = t2.SUBMENU_ID WHERE (t1.IS_ACTIVE = 'Y') ORDER BY `parent_id` ASC, `t2`.`DISPLAY_ORDER` ASC
问题:Oracle DB无法在[t1.MENU_ID = t2.SUBMENU_ID]中标识t1和t2,除非它们用双引号引起来。而且,如果我手动输入双引号,则mysql会出错。
Oracle中的错误:
一般错误:904 OCIStmtExecute:ORA-00904:“ T2”。“ SUBMENU_ID”: 无效的标识符
答案 0 :(得分:0)
解决了。使用$ db-> quoteIdentifier()。而且有效
$db = Zend_Db_Table::getDefaultAdapter();
$db->setFetchMode(Zend_Db::FETCH_OBJ);
$select = $db->select()->from(array(
't1' => $this->_Table1
));
$select = $select->join(array(
't2' => $this->_Table2
), $db->quoteIdentifier('t1.MENU_ID') . ' = ' . $db->quoteIdentifier('t2.SUBMENU_ID'),
array(
'MENU_ID',
'SET_REDIRECT_URL',
'SUBMENU_TYPE'
));
$select = $select->order(array(
'MENU_ID',
't2.DISPLAY_ORDER'
));
$select = $select->where($db->quoteIdentifier('t1.IS_ACTIVE') . ' = ?', 'Y');
$result = $db->fetchAll($select);