如何从JSONArray获取给定值的最后一个JSON对象？

Question

我有如下所示的JSONArray

[
    {
        "id": 1,
        "firstName": "abc",
        "isActive": true
    },
    {
        "id": 2,
        "firstName": "cde",
        "isActive": false
    },
    {
        "id": 3,
        "firstName": "efg",
        "isActive": true
    },
    {
        "id": 4,
        "firstName": "ghi",
        "isActive": false
    }
]

现在，我想使用最有效和最优化的方法从该数组中获得值“ isActive”的值为true的对象。

{
    "id": 3,
    "firstName": "efg",
    "isActive": true
}

更新：

let getLast = items.filter（item => item.isActive === true）;

我尝试使用@brk提供的解决方案。但是有什么方法可以使用对象而无需创建新数组。

Answer 1

第一个filter，条件为isActive === true。这将创建一个新数组，然后使用array.length-1获取最后一个元素

let data = [{
    "id": 1,
    "firstName": "abc",
    "isActive": true
  },
  {
    "id": 2,
    "firstName": "cde",
    "isActive": false
  },
  {
    "id": 3,
    "firstName": "efg",
    "isActive": true
  },
  {
    "id": 4,
    "firstName": "ghi",
    "isActive": false
  }
]

let getLast = data.filter(item => item.isActive === true);
console.log(getLast[getLast.length - 1])

Answer 2

var x=[
  {
    "id": 1,
    "firstName": "abc",
    "isActive": true
  },
  {
    "id": 2,
    "firstName": "cde",
    "isActive": false
  },
  {
    "id": 3,
    "firstName": "efg",
    "isActive": true
  },
  {
    "id": 4,
    "firstName": "ghi",
    "isActive": false
  }
];

//Try the following line

x.filter(x=>x.isActive).slice(-1).pop()

Answer 3

var jsonObject = [
  {
    "id": 1,
    "firstName": "abc",
    "isActive": true
  },
  {
    "id": 2,
    "firstName": "cde",
    "isActive": false
  },
  {
    "id": 3,
    "firstName": "efg",
    "isActive": true
  },
  {
    "id": 4,
    "firstName": "ghi",
    "isActive": false
  }
];

var lastActiveElement = jsonObject.filter( obj => obj.isActive ).pop();

console.log(lastActiveElement);

如果这是您要寻找的