Question

我是使用json文件的新手，我已经构造了一个分层的json对象，我试图在android studio Toast中显示这些值，但是其中一些是关键值，我不希望它们显示出来，但是它们正在显示过程中，请指导做错了什么

这是json文件的一部分（json数组中的单个对象）

 {
    "county": "Nyeri",
    "subcounty": ["Kieni East", [{
        "ward": ["funny", [{
            "policestation": ["null"]
        }], "kkkkk", [{
            "policestation": ["null"]
        }]]
    }], "Kieni West", [{
        "ward": "null"
    }], "Mathira East", [{
        "ward": ["Magutu", [{
            "policestation": ["Magutu", [{
                "arbitrator": ["null"]
            }], "Magutu ps", [{
                "arbitrator": ["null"]
            }], "Kagochi PS", [{
                "arbitrator": ["null"]
            }]]
        }], "Iriani", [{
            "policestation": ["null"]
        }], "Konyu", [{
            "policestation": ["null"]
        }], "Kirimukuyu", [{
            "policestation": ["null"]
        }], "Karatina Town", [{
            "policestation": ["Kagochi PS", [{
                "arbitrator": ["null"]
            }], "Gitunduti PS", [{
                "arbitrator": ["christopher bundi", "silvester kasanga"]
            }]]
        }]]
    }], "Mukurweini", [{
        "ward": "null"
    }], "Tetu", [{
        "ward": ["rulie", [{
            "policestation": ["null"]
        }]]
    }]]
 }

这是代码，并试图通过不包括病房列表的键来访问子县

  try {
  JSONArray jsonArray = new JSONArray (response);

 for (int i = 0; i < jsonArray.length (); i++) {
   JSONObject jsonObject = jsonArray.getJSONObject (i);

  String subcounty = jsonObject.getString ("subcounty");
  Toast.makeText (getApplicationContext (), subcounty, Toast.LENGTH_LONG).show ();}//close try and catch follows

面临的挑战是选择子县的值，以免除那些对病房很关键的值。感谢您提供支持

Answer 1

通过将阵列修改为正确的格式，即 [{ “ county”：“ Mombasa”， “子县”：[{ “ subcountyname”：“ mtwapa”， “病房”：[{ “ wardname”：“有趣”， “警察局”： [{ “ stationame”：“ Magutu ps”， “仲裁员”：[{ “ arbitratorname”：“ christopher bundi” }] }] }] }，{ “ subcountyname”：“ likoni”， “病房”：[{ “ wardname”：“空” }] }，{ “ subcountyname”：“ hihi”， “病房”：[{ “ wardname”：“空” }] }，{ “ subcountyname”：“ mambo”， “病房”：[{ “ wardname”：“空” }] }] }，{ “ county”：“ Kwale”， “子县”：[{ “ subcountyname”：“空” }] }] 然后我可以通过循环从数组访问数据通过初始数组中的对象。在这个带有对象子县的级别上，我可以在其中获取数组，，，得到该数组中的对象子县名称，以此类推，为了更清楚起见，请参考Parsing JSON array and object in Android

Answer 2

使用以下代码和JsonFormat，希望对您有所帮助。

String response = "[{"name":"Country 1", "subs": ["sub1","sub2","sub3"] },{"name":"Country 2", "subs": ["subWest1","subWest2","subWest3"] }]";
        try{
            JSONArray mainList = new JSONArray(response);
            ArrayList<String>   countries   =   new ArrayList<>();
            ArrayList<String>   subs   =   new ArrayList<>();

            for (int a=0;a<mainList.length();a++){
                JSONObject object=mainList.getJSONObject(a);
                countries.add(object.getString("name"));
                subs.add(object.getString("subs"));
            }

            setAdapterForCountries(countries);
        }catch(JSONException e){
            e.printStackTrace();
        }

在项目选择回调上执行此操作

////On Item Select
            JSONArray   subCountries    =   new JSONArray(subs.get(selectedItemPosition));
            setSubCountiresAdapter(subCountries);

这是从该JSONArray获取字符串列表的方法。

private void setSubCountiresAdapter(JSONArray   subs){
    ArrayList<String>   subsNames   =   new ArrayList<>();
    for (int a=0;a<subs.length();a++){
        try {
            subsNames.add(subs.getString(a));
        } catch (JSONException e) {
            e.printStackTrace();
        }
    }
}

从Android Studio加载多层Json文件不一致

2 个答案: