Question

我想运行一个节点应用程序，该应用程序将检查多个网站并以正确的状态代码进行响应。我正在使用Node本身的“请求”模块。

我的代码是：

const request = require('request')

function getStatus() {
    request('https://www.google.com', function(error, response, body) {

        result = response.statusCode;

        if(!error && response.statusCode == 200) {
            document.write("The Site Is Up");
            console.log(result);
        } else {
            console.log("The Site Is Down");
        }
    });
}

这对于一个网站正常工作。但是，我想知道如何为多个站点运行相同的功能？例如，应从一组网址中获取该网址。

如果我有一个网址数组，例如：

var urls = ["https://www.google.com", "https://www.yahoo.com"];

如何将这些单独的网址提供给请求函数？并获得每个网站的结果？

Answer 1

您可以使用承诺列表来做到这一点，应该很容易做到：

const request = require('request')

const urlList = ["https://www.google.com", "https://www.amazon.com"];

function getStatus(url) {
    return new Promise((resolve, reject) => {
        request(url, function(error, response, body) {
            resolve({site: url, status: (!error && response.statusCode == 200) ? "OK": "Down: " + error.message});
        });
    })   
}

let promiseList = urlList.map(url => getStatus(url));

Promise.all(promiseList).then(resultList => {
    resultList.forEach(result => console.log("Result: ", result));
});

您还可以使用我们的request-promise-native库获得更好的API：

    const request = require('request')
    const rp = require('request-promise-native')

    const urlList = ["https://www.google.com", "https://www.amazon.com", "https://doesnotexist.none", "https://wikipedia.org"];

    function getStatusRp(url) {
        return rp({uri: url, resolveWithFullResponse: true }).then((response) => {
            return { site: url, status: response.statusCode === 200 ? "OK": "Down"};
        }, (err) => {
            return { site: url, status: "Down: " + err.message};
        });
    }

    let promiseList = urlList.map(url => getStatusRp(url));

    Promise.all(promiseList).then(resultList => {
        resultList.forEach(result => console.log("Result: ", result));
    });

使用Node JS进行多个网站状态检查

1 个答案: