Question

我的服务因CXF故障得到400响应，我找不到400的设置位置，

我到处搜索，未找到此异常的异常映射器，响应是tomcat格式的html

始于Apache Tomcat / 8.0.46的东西-错误报告

这使我相信它没有映射到适当的响应，

但是我认为应该是500，而不是400

是否有任何方法可以显示拦截器的位置，例如CXF中调试器控制台输出的详细选项？

感谢一百万！

05 Mar 2019 09:58:36,402 DEBUG [http-nio-8080-exec-4] - x-dxe-requestid=bd5f3c71-0fe7-4ed7-80f6-46049db8b26d Chain org.apache.cxf.phase.PhaseInterceptorChain@e16a6b5 was created. Current flow:
  prepare-send [MessageSenderInterceptor]
  marshal [JAXRSDefaultFaultOutInterceptor]

05 Mar 2019 09:58:36,402 DEBUG [http-nio-8080-exec-4] - x-dxe-requestid=bd5f3c71-0fe7-4ed7-80f6-46049db8b26d Invoking handleMessage on interceptor org.apache.cxf.interceptor.MessageSenderInterceptor@51645fab
05 Mar 2019 09:58:36,402 DEBUG [http-nio-8080-exec-4] - x-dxe-requestid=bd5f3c71-0fe7-4ed7-80f6-46049db8b26d Adding interceptor org.apache.cxf.interceptor.MessageSenderInterceptor$MessageSenderEndingInterceptor@33fad37 to phase prepare-send-ending
05 Mar 2019 09:58:36,402 DEBUG [http-nio-8080-exec-4] - x-dxe-requestid=bd5f3c71-0fe7-4ed7-80f6-46049db8b26d Chain org.apache.cxf.phase.PhaseInterceptorChain@e16a6b5 was modified. Current flow:
  prepare-send [MessageSenderInterceptor]
  marshal [JAXRSDefaultFaultOutInterceptor]
  prepare-send-ending [MessageSenderEndingInterceptor]

05 Mar 2019 09:58:36,402 DEBUG [http-nio-8080-exec-4] - x-dxe-requestid=bd5f3c71-0fe7-4ed7-80f6-46049db8b26d Invoking handleMessage on interceptor org.apache.cxf.jaxrs.interceptor.JAXRSDefaultFaultOutInterceptor@21747905
05 Mar 2019 09:58:36,402 DEBUG [http-nio-8080-exec-4] - x-dxe-requestid=bd5f3c71-0fe7-4ed7-80f6-46049db8b26d Invoking handleFault on interceptor org.apache.cxf.jaxrs.interceptor.JAXRSDefaultFaultOutInterceptor@21747905
05 Mar 2019 09:58:36,402  WARN [http-nio-8080-exec-4] - x-dxe-requestid=bd5f3c71-0fe7-4ed7-80f6-46049db8b26d Exception in handleFault on interceptor org.apache.cxf.jaxrs.interceptor.JAXRSDefaultFaultOutInterceptor@21747905
org.apache.cxf.interceptor.Fault: com.dxe.comm.domain._2012_11_01.ComTransaction.setTransactionNetworkId(Ljava/lang/String;)V
    at org.apache.cxf.service.invoker.AbstractInvoker.createFault(AbstractInvoker.java:162)

Answer 1

发现它是在我们自己的代码中设置的：javax.servlet.Filter.doFilter，这是一个严重的错误。

如何显示cxf错误在哪里被拦截？

1 个答案: