Question

这里我在arrayData中有arrayData数组对象，我有多个对象，我想从该数组对象中删除索引并键入键值，如何从此arrayData中删除？

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删除索引和类型后，我希望得到这种类型的结果

arrayData : [
  0: {
       index: 0
       is_required: true
       name: "vmvdnksl"
       type: "LONG_TEXT"
     }
  1: {
       index: 1
       is_required: true
       name: "dsvnlk"
       type: "MULTIPLE_SELECTORS"
     }
   ]

Answer 1

您可以使用rest参数。当你有很多东西的时候会很方便您想要保留的密钥并仅删除其中的几个。

const arrayData= [{index: 0,is_required: true,name: "vmvdnksl",type: "LONG_TEXT"},{index: 1,is_required: true,name: "dsvnlk",type: "MULTIPLE_SELECTORS"}];

const result = arrayData.map(({type,index,...rest}) => ({...rest}));

console.log(result);

Answer 2

您可以使用delete关键字从对象中删除属性。

var arrayData = [
  0: {
       index: 0,
       is_required: true,
       name: "vmvdnksl",
       type: "LONG_TEXT"
     },
  1: {
       index: 1,
       is_required: true,
       name: "dsvnlk",
       type: "MULTIPLE_SELECTORS"
     }
 ];

for (var i in arrayData) {
  for (var j in arrayData[i]) {
    if (j === 'index' || j === 'type') {
      delete arrayData[i][j];
    }
  }
}

console.log(arrayData);

Answer 3

您可以使用Array.map()和destructuring来完成此任务：

const arrayData = [
    {
       index: 0,
       is_required: true,
       name: "vmvdnksl",
       type: "LONG_TEXT"
     },
     {
       index: 1,
       is_required: true,
       name: "dsvnlk",
       type: "MULTIPLE_SELECTORS"
     }
];

let res = arrayData.map(({is_required, name}) => ({is_required, name}));
console.log(res);

.as-console {background-color:black !important; color:lime;}
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我宁愿永远不对原始数据进行突变，但是在您需要这种情况的情况下，您可以采用这种方式（或使用delete，如其他人所展示的那样）：

const arrayData = [
    {
       index: 0,
       is_required: true,
       name: "vmvdnksl",
       type: "LONG_TEXT"
     },
     {
       index: 1,
       is_required: true,
       name: "dsvnlk",
       type: "MULTIPLE_SELECTORS"
     }
];

let res = arrayData.forEach(
    ({is_required, name}, idx, arr) => arr[idx] = ({is_required, name})
);
console.log(arrayData);

.as-console {background-color:black !important; color:lime;}
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Answer 4

尝试使用JavaScript的delete operator，如以下代码示例所示：

for(let o in arrayData){
    delete arrayData[o].index;
    delete arrayData[o].type
}

Answer 5

对于数组，您可以使用map()函数

    var arrayData = [
      {
           index: 0,
           is_required: true,
           name: "vmvdnksl",
           type: "LONG_TEXT"
      },
      {
           index: 1,
           is_required: true,
           name: "dsvnlk",
           type: "MULTIPLE_SELECTORS"
      }
    ],
    mappedArrayData = arrayData.map(({is_required, name}) => {
       return {is_required, name};
    })
    
    console.log(mappedArrayData);

对于对象，请使用delete运算符。

var arrayData = {
  0: {
       index: 0,
       is_required: true,
       name: "vmvdnksl",
       type: "LONG_TEXT"
     },
  1: {
       index: 1,
       is_required: true,
       name: "dsvnlk",
       type: "MULTIPLE_SELECTORS"
     }
  };
  
  
for (let key in arrayData) {
  delete arrayData[key].index;
  delete arrayData[key].type;
}
  
console.log(arrayData);

Answer 6

您可以简单地使用Array.map()仅显示必需的属性：

const arrayData= [
   {
       index: 0,
       is_required: true,
       name: "vmvdnksl",
       type: "LONG_TEXT"
     },
   {
       index: 1,
       is_required: true,
       name: "dsvnlk",
       type: "MULTIPLE_SELECTORS"
     }
   ];

const result = arrayData.map(({is_required, name}) => ({is_required, name}));

console.log(result);

如何从JavaScript中的数组对象中删除特定的键和值？

6 个答案: