Question

我有拖曳桌：

客户：

name
-----
TOMMY 
LOUIE 
HUGO 
OLLIE 
DAVID 
LEWIS 
JACKSON

员工：

name     | stage
---------+---------
OLIVER   |  1
NOAH     |  1
ALFIE    |  1
OSCAR    |  2
NOAH     |  2
OLIVER   |  2
LEO      |  2

在员工中，我有两个阶段。在每个阶段中，它可以拥有相同的员工还是不同的员工，我想在两个条件下将客户划分或分配给员工：

第一阶段的客户必须在第二阶段拥有不同的员工
每个员工在每个阶段中必须拥有相同数量的客户，并且每个客户在每个阶段中都必须具有1名员工，且不能重复。

我已经用游标完成了将结果插入到不同表中的过程，但问题是，将第1阶段的客户重复给第2阶段的同一员工（例如，NOAH取相同的Customer）会产生错误的结果

CREATE  PROCEDURE AUDIT_Customer   AS

CURSOR Customer_STAGE1 IS SELECT * FROM (
                select
                      s.name  Customer_name
                      ,t.name Employees_name 
                from (select name, row_number() over(order by name) as rn from Employees  WHERE stage = 1 ) t
                join (select name, row_number() over(order by name) as rn from Customer  ) s
                on mod(s.rn - 1, (select count(*) from Employees WHERE stage = 1)) = t.rn -1); 


CURSOR Customer_STAGE2 IS SELECT * FROM (
                select
                      s.name  Customer_name
                      ,t.name Employees_name 
                from (select name, row_number() over(order by name) as rn from Employees  WHERE stage = 2 ) t
                join (select name, row_number() over(order by name) as rn from Customer   ) s
                on mod(s.rn - 1, (select count(*) from Employees WHERE stage = 2)) = t.rn -1);                 


Begin 
      For y in  Customer_STAGE1 Loop

             Insert  into Customer_Employee(Customer_name,Employees_name,RECIVE_DATE,stage)
             Values  (Y.Customer_name ,Y.Employees_name,sysdate,1) ;

      End Loop ;

       For y in  Customer_STAGE2 Loop

             Insert  into Customer_Employee(Customer_name,Employees_name,RECIVE_DATE,stage)
             Values  (Y.Customer_name ,Y.Employees_name,sysdate,2) ;

      End Loop ;


   COMMIT;               
End AUDIT_Customer;

结果：

    Customer| Employees| stage
    --------+--------- +---------
    TOMMY   | OLIVER   |  1
    LOUIE   | OLIVER   |  1
    HUGO    | NOAH     |  1
    OLLIE   | NOAH     |  1
    DAVID   | ALFIE    |  1
    LEWIS   | ALFIE    |  1
    JACKSON | ALFIE    |  1
    TOMMY   | OSCAR    |  2
    LOUIE   | OSCAR    |  2
    HUGO    | NOAH     |  2
    OLLIE   | NOAH     |  2
    DAVID   | OLIVER   |  2
    LEWIS   | OLIVER   |  2
    JACKSON | LEO      |  2

我该如何解决？

Answer 1

过滤过程的第二部分这可能会帮助：

(select name, row_number() over(order by name) as rn from Employees  WHERE stage = 2 and Employee.Name not in (select Employee.Name from Employee WHERE stage = 1))

Oracle SQL：将另一行中的一行划分为另一行，而不必根据变量值进行重新导入

1 个答案: