Question

我试图用字典键匹配列表值并打印出来。

问题：打印输出看起来很糟糕。

marbles = {"red": 34, "green": 30, "brown": 31, "yellow": 29 }

myLst=["red","orange"]

for k,v in marbles.items():
    for item in myLst:
        if item in k:
            print('Found',item)
        else:
            print('Not Found',item)

输出：

Not Found red
Not Found orange
Not Found red
Not Found orange
Found red
Not Found orange
Not Found red
Not Found orange

我用这种方法解决了这个问题：将密钥放在另一个列表中，然后比较2个列表，它们的输出效果很好：

mrblKeyList=[] #empty list to put the keys


for key in marbles.keys():
    mrblKeyList.append(key)
print (mrblKeyList)

for item in myLst:
    if item in mrblKeyList:
        print('Found',item,' in both lists')
    else:
        print('Did not find',item, 'in both lists')

在第一种方法中，我可以压缩，压缩或其他任何方法吗？预先感谢您的宝贵时间。

将列表值与字典匹配，然后打印Python

0 个答案: