如何在SQL Server中计算借方和贷方余额?

时间:2019-03-06 03:29:37

标签: sql sql-server-2012

我有桌子:

  • 客户(Id_Customer,名称,地址)

       (1,A, Add1)
       (2,B, Add2)
       (3,C, Add3)
       (4,D, Add4)    
       (5,E, Add5)    
    
  • 收据(客户ID,资金)

       (2, 10)
       (3, 20)
       (2, 15)
    
  • 付款(Id_Customer,资金)

       (1, 30)
       (2, 40)
       (4, 05)
    

现在,我要显示如下:

Name   -------   Debit balance  ------    In credit    
A       ----------------------------------------30

B ----------------15-------------------------

C    -----------------------------------------20

D  -------------- 05-----------------------


Total DB: -----   20-------------Total IC: 50

其中:

if sum(money) of Receipt < sum(money) of Payment 
   then Debit balance = sum(money) of Payment - sum(money) of Receipt 
else 
   In credit = sum(money) of Receipt-sum(money) of Payment

注意,仅当借方余额或贷方不为零时显示客户。总计超过()进行分页。

我使用QUERY运行,但是仅显示在两个表中的“收款”和“付款”中也有“钱”的客户(如果客户只在“收据”中有钱,否则“付款”将不会显示在结果中,为什么?显示那个顾客?)

select a.*, Total_DebitBalance=sum(DebitBalance) over (), Total_InCredit=sum(InCredit) over () from (SELECT C.name, C.Address,

CASE WHEN SUM(isnull(R.Money, 0))< SUM(isnull(P.Money, 0)) THEN SUM(isnull(P.Money, 0)) - SUM(isnull(R.Money, 0)) END AS DebitBalance,

CASE WHEN SUM(isnull(R.Money, 0))> SUM(isnull(P.Money, 0)) THEN SUM(isnull(R.Money, 0)) - SUM(isnull(P.Money, 0)) END AS InCredit,

C.Id_Customer, COUNT(*) OVER () AS total_count

FROM Customer C LEFT JOIN Receipt R ON C.Id_Customer = R.Id_Customer LEFT JOIN Payment P ON C.Id_Customer = P.Id_Customer group by C.Id_Customer, C.name, C.Address)a ;

这是结果:

姓名-------借方余额------贷方

B ----------------15-------------------------

Total DB: -----   15-------------Total IC: 0

1 个答案:

答案 0 :(得分:0)

修改后的查询。 (很抱歉延迟)

以下应满足您的需求

SELECT 
    C.Id_Customer,
    CASE 
       WHEN ISNULL(R.[Money], 0) - ISNULL(P.[Money], 0)> 0 
          THEN ISNULL(R.[Money], 0) - ISNULL(P.[Money], 0)
    END AS [Debit balance],
    CASE 
       WHEN ISNULL(P.[Money], 0) - ISNULL(R.[Money], 0) > 0 
          THEN ISNULL(P.[Money], 0) - ISNULL(R.[Money], 0)
    END AS [In credit]

FROM
    Customer C
LEFT JOIN 
    (SELECT SUM([Money]) AS [Money],Id_Customer FROM Receipt GROUP BY Id_Customer) R ON C.Id_Customer = R.Id_Customer
LEFT JOIN 
    (SELECT SUM([Money]) AS [Money],Id_Customer FROM Payment GROUP BY Id_Customer)P ON C.Id_Customer = P.Id_Customer