Question

在我的Codepen中可以看到，有两种灰度形状。现在，它只能悬停两者之一，因为原始大小是一个盒子并且与两个图像重叠。但是，有没有一种方法喜欢在悬停时识别形状？ Z-index不会导致结果... 希望你能帮我一下！没有JS会很棒，但不是k.o。

html：

<div id="one">
<img src="https://cdn.pixabay.com/photo/2019/01/19/15/53/ice- 
3941906_1280.jpg">
 </div>
<div id="two">
<img src="https://cdn.pixabay.com/photo/2016/04/20/17/02/tuscany- 
1341536_1280.jpg">
</div>

css：

img{
  width: 700px;
  height: 400px;
  object-fit: cover;
}

#one img{
  -webkit-clip-path: polygon(0 0, 0% 100%, 100% 0);
clip-path: polygon(0 0, 0% 100%, 100% 0);
}

#two img{
  -webkit-clip-path: polygon(100% 100%, 0% 100%, 100% 0);
clip-path: polygon(100% 100%, 0% 100%, 100% 0);
}

#one{
  position: absolute;
  z-index: 0;
  top: 0 ;
  left: 0;
}

#two{
position:absolute;
  top: 0px;
  left: 0;
  z-index: 0;
}

#one,
#two{
  filter:grayscale(100%);
}

#one:hover,
#two:hover{
  filter:grayscale(0%);
}

https://codepen.io/robwe30/pen/eXBvzp?editors=1100

欢呼

Answer 1

对于那种简单的形状，您可以玩pointer-events来删除它，并旋转一个伪元素以仅在图像的一部分上将其切换回去。

关于指针事件https://css-tricks.com/almanac/properties/p/pointer-events/

示例

/* CSS switch of  pointer-events  on/off */

#two {
  position: relative;
  overflow: hidden;/* hide pseudo overflowing */
  pointer-events: none;
}

#two:before {
  pointer-events: auto;
  content: '';
  position: absolute;
  top: 100%;
  left: 0;
  z-index: 2;
  width: 150%;
  height: 100%;
  
  /* set transform according to ratio image */
  transform-origin: top left;
  transform: rotate(-30deg);
  
  /* if you want to see where it stands , add borders or background */
}


/* end CSS  switch */

img {
  width: 700px;
  height: 400px;
  object-fit: cover;
  display: block;/* avoids gap underneath */
}

#one img {
  -webkit-clip-path: polygon(0 0, 0% 100%, 100% 0);
  clip-path: polygon(0 0, 0% 100%, 100% 0);
}

#two img {
  -webkit-clip-path: polygon(100% 100%, 0% 100%, 100% 0);
  clip-path: polygon(100% 100%, 0% 100%, 100% 0);
}

#one {
  position: absolute;
  z-index: 0;
  top: 0;
  left: 0;
}

#two {
  position: absolute;
  top: 0px;
  left: 0;
  z-index: 0;
}

#one,
#two {
  filter: sepia(100%);/* demo purpose */
}

#one:hover,
#two:hover {
  filter: grayscale(0%);
}

<div id="one">
  <img src="https://picsum.photos/800/600?image=1060">
</div>
<div id="two">
  <img src="https://picsum.photos/800/600?image=1065">
</div>

https://codepen.io/gc-nomade/pen/aMBwYz

Answer 2

这是使用更少的代码并且没有clip-path

来创建相同内容的另一个想法

.container {
  width: 300px;
  height: 200px;
  position: relative;
  overflow: hidden;
}

.container img {
  width: 100%;
  height: 100%;
  object-fit: cover;
  display: block;
}

.container div {
  position: absolute;
  top: 0;
  left: 0;
  width: 100%;
  height: 100%;
  transform: skewX(-56.3deg); /* tan(angle) = Width/height --> angle = arctan(width/height) */
  transform-origin: top;
  overflow: hidden;
}

.container div img {
  transform: skewX(56.3deg);
  transform-origin: top;
}
.container img:hover{
   filter:grayscale(100%);
}

<div class="container">
  <img src="https://picsum.photos/800/600?image=1069">
  <div>
    <img src="https://picsum.photos/800/600?image=1051">
  </div>
</div>

CSS剪切路径仅在形状上悬停

2 个答案: