我有以下超人类型的对象。我需要它两次调用一个方法,一次是从超人类,一次是从ActionCharacter -parent。该怎么做?
interface CanFight {void fight();}
interface CanFly {void fly();}
interface interface CanClimb{void climb();}
interface CanSwim{
void swimFast();
void treadH2O();
}
class ActionCharacter {
public void fight() {System.out.println("fight an ActionChar");}
}
class Superman extends ActionCharacter implements CanFight, CanFly, CanClimb, CanSwim{
String name = "Superman";
public void fight() {System.out.println("fight bad guys");}
public void fly() {System.out.println("fly faster than a bird");}
public void swimFast() {System.out.println("Swim faster than Michael Phelps");}
public void treadH2O() {System.out.println("Tread water forever");}
public void climb() {System.out.println("climb vertical cliffs");}
}
public class Action {
public static void t(CanFight x) { x.fight(); }
public static void v(CanFly x) { x.fly(); }
public static void w(ActionCharacter x) { x.fight();}
public static void x(CanClimb x) {x.climb();}
public static void y(CanSwim x) {x.swimFast(); x.treadH2O();}
public static void main(String[] args) {
Superman h = new Superman();
System.out.println("I am " + h.name + " I can do the following:" );
t(h); // Treat it as a CanFight
y(h);
v(h); // Treat it as a CanFly
x(h);
w(h); //This should print fight an ActionChar
ActionCharacter i = (ActionCharacter)h;
w(i); //Second attempt to print fight an ActionChar
}
}
答案 0 :(得分:0)
在您的超类ActionCharacter
中定义该方法,并在您的子类Superman
中对其进行覆盖,因此两个对象(超人类型和ActionCharacter类型)都可以使用此方法
答案 1 :(得分:0)
java中的 super 关键字是一个引用变量,用于引用父类对象
在超人类中:
fight();
要从ActionCharacter父级进行调用:
super.fight();