我试图绘制频率与不同状态(0-3)之间跃迁数的关系。但是,在那些包含“零”状态的图中,我得到了空图。将状态等级更改为1-4可以解决空图的问题,但是,图标题不正确。我看到this线程指出循环可以从零开始。有什么解决方法可以避免这些空图?
代码如下:
n_IDs <- 150
TIME <- 0:100
set.seed(1)
(markov <- data.frame(ID=rep(1:n_IDs,each=length(TIME)),
TIME=rep(TIME,n_IDs),
STATE=sample(0:3,n_IDs*length(TIME),replace=TRUE)))
transitions <- data.frame(ID=head(markov$ID,-1),
TIME=tail(markov$TIME,-1),FROM=head(markov$STATE,-1),TO=tail(markov$STATE,-1))
transition_table <- with(transitions,table(FROM,TO,ID))
min_n_transitions <- min(unlist(transition_table))
max_n_transitions <- max(unlist(transition_table))
max_freq <- 50
par(mfrow=rep(4,2),mai=c(.3,.3,.3,.1))
for ( from in 0:3 ) {
for ( to in 0:3 ) {
foo <- transition_table[from,to,]
hist(foo,freq=TRUE,
breaks=seq(min_n_transitions-.5,max_n_transitions+0.5),
xlim=c(min_n_transitions,max_n_transitions),
ylim=c(0,max_freq),xlab="",ylab="",
main=paste("From",from,"to",to),
las=1,col="lightgray")
mtext('Number of transitions', side = 1, outer = TRUE, line = 2)
mtext('Frequency', side = 2, outer = TRUE, line = 1.5)
}
}
提前谢谢!
答案 0 :(得分:0)
问题是您要使用from
和to
作为行/行,而您要起诉from
和to
作为索引号,并且在R中不存在索引0。列名,您应该将其用作字符,
如果您将定义foo
的行更改为以下行,则应该可以正常工作
foo <- transition_table[as.character(from), as.character(to), ]