因此,在过去的几天中,我尝试使发生新情况时自动重新加载此模板。就是在修改“通知”时,要么添加新条目,要么将通知标记为已读。
我使用下拉菜单显示结果,现在当发生某些情况时,我必须重新加载整个页面。对于现代应用程序来说,这不是很好。
PS。我对Vue完全陌生,因为它与laravel通知集成在一起。
这是我的.vue文件(您可以看到我自己尝试了一些尝试但没有成功)
<template>
<li class="dropdown">
<a href="#" class="dropdown-toggle icons" data-toggle="dropdown" role="button"
aria-haspopup="true" aria-expanded="false">
<span class="badge badge-dark badge-corner fs-11">{{ notifications.length }}</span>
<i class="fas fa-bell fs-15" style="color: #444;"></i>
</a>
<ul
class="dropdown-menu dropdown-menu-right notify-drop">
<li>
<div class="notify-drop-title">
<div class="row">
<div class="col-10">Notifikationer (<b>{{ notifications.length }}</b>)</div>
<div class="col-2 text-right">
<button class="rIcon allRead"
data-tooltip="tooltip"
data-placement="bottom"
title="Markera alla som lästa"><i
class="fa fa-bullseye fs-12"></i>
</button>
</div>
</div>
</div>
<!-- end notify title -->
<!-- notify content -->
<div class="drop-content">
<div class="thisItem" v-for="notification in notifications" :key="notification.id">
<div class="row pl-10">
<div class="col-1">
<div
v-if="notification.data.type === 'friend' || notification.data.type === 'friendAccept'">
<i class="fas fa-heart fs-25 primary mt-5"></i>
</div>
<div v-if="notification.data.type === 'friendDeny'">
<i class="fas fa-heart-broken fs-25 primary mt-5"></i>
</div>
</div>
<div class="col-10 ml-5">
<button class="float-right rIcon mr-1" data-toggle="tooltip"
data-placement="top" title="Markera som läst"
v-on:click="MarkAsRead(notification)">
<i class="fa fa-bullseye fs-12"></i>
</button>
<a class="fs-14 m-0" style="text-transform: none;" :href="'/profile/' + notification.data.accessurl">{{
notification.data.fromuser }}</a>
<span class="fs-12 m-0 text-muted">{{ notification.data.message }}</span>
<div v-if="notification.data.type === 'friend'">
<button type="button" class="btn btn-primary btn-sm"
v-on:click="AcceptFriend(notification)">Acceptera
</button>
<button type="button" class="btn btn-primary btn-sm"
v-on:click="DenyFriend(notification)">Neka
</button>
</div>
</div>
</div>
</div>
</div>
<div class="notify-drop-footer text-center">
<a href=""><i class="fa fa-eye"></i> Visa Alla</a>
</div>
</li>
</ul>
</li>
</template>
<script>
export default {
props: ['notifications'],
methods: {
MarkAsRead: function (notification) {
const data = {
id: notification.id
};
const self = notification;
axios.post('/notification/read', data).then(response => {
//self.id = '';
//self.$forceUpdate();
//self.notification += 1;
//self.setState({notification: response.data});
//self.data.fromuser = '';
//self.data.message = response.data;
//this.notifications.splice(notification,1);
console.log(response.data);
});
},
AcceptFriend: function (notification) {
const data = {
id: notification.id,
friendid: notification.data.itemid,
fromuserid: notification.data.fromuserid
};
axios.post('/notification/acceptFriend', data).then(response => {
console.log(response.data);
});
axios.post('/notification/read', data).then(response => {
console.log(response.data);
});
},
DenyFriend: function (notification) {
const data = {
id: notification.id,
friendid: notification.data.itemid,
fromuserid: notification.data.fromuserid
};
axios.post('/notification/denyFriend', data).then(response => {
console.log(response.data);
});
axios.post('/notification/read', data).then(response => {
console.log(response.data);
});
}
}
}
</script>
我的app.js
Vue.component('notification', require('./components/Notification.vue'));
const app = new Vue({
el: '#app',
data: {
notifications: ''
},
created() {
axios.post('/notification/get').then(response => {
this.notifications = response.data;
});
var userId = $('meta[name="userId"]').attr('content');
Echo.private('App.User.' + userId).notification((notification) => {
this.notifications.push(notification);
});
},
computed: {
notifications: function () {
return this
}
}
});
在此先感谢您能帮助我解决这个问题的人!
答案 0 :(得分:0)
据我了解,您是否希望每次收到新的通知数据时都呈现多个通知?
在这种情况下,您可以使用props
。
如果您将props
注入通知组件,则props
更改时,通知组件将重新呈现
示例
<notification :notifications='notifications'><notification>