Question

给定表包含

employee_id, 
Month_Year, 
Salary, 
City

编写查询以从每个城市获得年薪第五高的员工。

我的代码：

select * from (select * from(select * from (select * from dummy order by sal desc) where rownum <= 5)  order by sal) where rownum <=1 ;

但这仅使总表中的排名第五。

我应该在哪里使用group by语句？

谢谢。

Answer 1

您可以在下面尝试-

select *
from tablename as t1 
where 
  t1.salary = (select salary from tablename t2
             where 
             t2.city= t1.city ORDER by salary desc limit 1 offset 5)

Answer 2

以下查询对我有用。（在条件为“ N”的情况下为number（4），其中“ N”为第n个最高薪水。在您的情况下，您希望第5个最高薪水，因此N-1为4）

find nth highest salary in sql

select salary,city 
FROM tablename n1
WHERE (4) = (
SELECT COUNT(DISTINCT(n2.Salary))
FROM tablename n2
WHERE n2.Salary > n1.Salary and n1.city=n2.city group by n2.city)

如何在SQL中使用group by，order by和where条件？

2 个答案: