Question

我有Spring Boot应用程序

它正在从ActiveMQ接收Json格式的消息

@Component class Receiver {
    @JmsListener(destination = "queue")
    public void receiveMessage(BusMessage message) {
        System.out.println("Received <" + message + ">");
    }

问题在于，有时Json会在没有正确头的情况下到达

在这种情况下，我会例外

org.springframework.messaging.converter.MessageConversionException: Cannot convert from [java.lang.String] to [cam.melexis.minipcs2socketioserver.BusMessage] for org.springframework.jms.listener.adapter.AbstractAdaptableMessageListener$MessagingMessageConverterAdapter$LazyResolutionMessage@38bd4ff9, failedMessage=org.springframework.jms.listener.adapter.AbstractAdaptableMessageListener$MessagingMessageConverterAdapter$LazyResolutionMessage@38bd4ff9

一种解决方案是将消息作为字符串获取并反序列化

@Component class Receiver {
    @JmsListener(destination = "queue")
    public void receiveScannerMessage(Message message, Session session) {
        System.out.println("Received <" + message + ">");
    }

但是我想做些更优雅的事情

要简化所有@JmsListener

并使我在Spring的学习曲线更加弯曲：）

知道什么，所有消息将以Json格式到达，我可以在所有传入消息中添加缺少的标头吗？

还是存在另一种“更好”的方式？

Answer 1

This made a job

@EnableJms
@Configuration class JmsListenerConfig implements JmsListenerConfigurer {

 Logger logger = LoggerFactory.getLogger(Receiver.class);

 @Bean
 public DefaultMessageHandlerMethodFactory handlerMethodFactory() {
    DefaultMessageHandlerMethodFactory factory = new DefaultMessageHandlerMethodFactory();
    factory.setMessageConverter(messageConverter());
    return factory;
 }

 @Bean
 public MessageConverter messageConverter() {
    return new MappingJackson2MessageConverter();
 }

 @Override
 public void configureJmsListeners(JmsListenerEndpointRegistrar registrar) {
    registrar.setMessageHandlerMethodFactory(handlerMethodFactory());
 }
}

But i have no idea how

Maybe anybody can help me with this?

为Spring Boot的传入消息添加缺少的ContentType

1 个答案: