这是我的第一个PHP项目,并且第一次遇到这个bug,经过一天的努力,它确实无法解决。 请问任何专家和友善的人在此建议如何解决此错误?我的PHP版本是5.6。
非常感谢您
提交表单后,它显示以下错误
致命错误:在第28行的null处调用成员函数prepare()
我的数据库连接编码为
<?php
$DSN= 'mysql:host = localhost; dbname=cms4.2.1';
$ConnectingDB = new PDO($DSN, 'root', '');
?>
Category page that shows line 28 got error on the POD function "prepare"
if(empty($Category))
{
$SESSION["ErrorMessage"] = "All fields must be filled out";
Redirect_to("Categories.php");
} elseif (strlen($Category)<3) {
$SESSION["ErrorMessage"] = "Category Title should be greater than 3
characters";
Redirect_to("Categories.php");
} elseif (strlen($Category)>49) {
$_SESSION["ErrorMessage"] = "Category Title should be less than 50
characters";
Redirect_to("Categories.php");
} else {
global $ConnectingDB;
$sql = "INSERT INTO category(title,author,datetime)";
$sql .="VALUES(:categoryName,:adminName,:dateTime)";
$stmt = $ConnectingDB->prepare($sql); // - > means PDO object rotation -
Line 28
$stmt->bindValue(':categoryName',$Category);
$stmt->bindValue(':adminName',$Admin);
$stmt->bindValue(':dateTime',$DateTime);
$Execute=$stmt->execute();
请协助。非常感谢。
答案 0 :(得分:2)
您可能需要在此处删除空格:mysql:host = localhost; dbname=cms4.2.1
将是mysql:host=localhost;dbname=cms4.2.1
此外,将连接语句包装在try-catch块中,以查看连接是否正确。
try {
$DSN = 'mysql:host=localhost;dbname=cms4.2.1';
$ConnectingDB = new PDO($DSN, 'root', '');
$ConnectingDB->setAttribute(PDO::ATTR_ERRMODE, PDO::ERRMODE_EXCEPTION);
echo 'Connected to Database<br/>';
}
catch(PDOException $e){
echo $e->getMessage();
}