我是熊猫和python的新手,所以遇到了一些麻烦。我有一个大的excel文件,我需要使用python脚本将其分为多个工作表。我必须根据数据中给出的IP地址进行划分。我不知道该怎么做,不胜感激。 我之前不了解使用python或任何库的知识。这是我所做的,但是为每一行创建了工作簿。
import pandas as pd
df = pd.read_excel("D:/Users/Zakir/Desktop/MyNotebooks/Legacy.xls", sheet_name="Total", header=0, names=None, index_col=None, parse_cols=None, usecols=None, squeeze=False, dtype=None, engine=None, converters=None, true_values=None, false_values=None, skiprows=None, nrows=None, na_values=None, keep_default_na=True, verbose=False, parse_dates=False, date_parser=None, thousands=None, comment=None, skipfooter=0, convert_float=True, mangle_dupe_cols=True)
writer = pd.ExcelWriter('D:/Users/Zakir/Desktop/MyNotebooks/pandas_simple.xlsx', engine='xlsxwriter')
for index, row in df.iterrows():
df1 = df.iloc[[index]]
df1.set_index('Number',inplace=True)
df1.to_excel(writer, sheet_name=row['IPAddress'])
writer.save()
答案 0 :(得分:0)
如果您有足够的内存,请采用一种解决方案:
from pandas import ExcelWriter
df = pd.read_excel('file',sheet_name="Total", header=0, #other settings.....#)
writer = ExcelWriter('E:/output.xlsx',engine='xlsxwriter')
print(df)
def writesheet(g):
a = g['IPAddress'].tolist()[0]
g.to_excel(writer, sheet_name=str(a), index=False)# index = True if you want to keep index
df.groupby('IPAddress').apply(writesheet)
writer.save()
答案 1 :(得分:0)
这是我实现代码的方法,用于检查文件夹,遍历所有excel文件并按列名的值分割每个文件,假设文件中有一张纸,可以将其作为输入(vColName)传递: / p>
import sys
import os, shutil
from os import listdir
from os.path import isfile, join
import pandas as pd
import urllib as ul
import datetime
import xlrd
#this method retrieves all the xlsx filenames from a folder
def find_excel_filenames( path_to_dir, suffix=".xlsx" ):
filenames = listdir(path_to_dir)
return [ filename for filename in filenames if filename.endswith( suffix ) ]
#this folder contains .xlsx files
filePath = "D:\files\sample\"
#there is a subfolder in my solution to move the processed files to
#and another subfolder to move the splitted output files
archivePath = os.path.join(filePath, "archive")
outPath = os.path.join(filePath, "output")
#get a list of filenames
fnames = find_excel_filenames(filePath)
#loop through each file
for fl in fnames:
vFile = os.path.join(filePath, fl)
#load the content of the file to a data frame,
#I open the file twice, first to get the number of columns and
#create the converter, then to open the file with string converter
#it helps with trimming of leading zeros
df = pd.read_excel(vFile, header=None)
column_list = []
for i in df:
column_list.append(i)
converter = {col: str for col in column_list}
df1 = pd.read_excel(vFile, converters=converter)
colValues=df1[vColName].unique().tolist()
for v in colValues:
filteredDF = df1.loc[df1[vColName]==v]
vOutFile = os.path.join(outPath, fl+''_''+v.replace("/"," ")+''.xlsx'')
writer = pd.ExcelWriter(vOutFile, engine=''xlsxwriter'')
# Convert the dataframe to an XlsxWriter Excel object.
filteredDF.to_excel(writer, sheet_name=''Sheet1'')
# Close the Pandas Excel writer and output the Excel file.
writer.save()
#move the processed file to an archive folder
dst_file = os.path.join(archivePath, fl)
if os.path.exists(dst_file):
os.remove(dst_file)
shutil.move(vFile, archivePath)