我有一个EditText
框,该框具有自定义的drawable
背景,但是每当您选择EditText
进行输入时,背景就会消失并且使文本无法阅读(这是与应用程序背景颜色相同)
这是我在说的:
背景消失了,我不确定为什么会这样。这是我的.xml
<EditText
android:id="@+id/enterCode"
android:layout_width="237sp"
android:layout_height="55sp"
android:layout_marginStart="8dp"
android:layout_marginTop="8dp"
android:layout_marginEnd="6dp"
android:layout_marginBottom="8dp"
android:autofillHints="true"
android:background="@drawable/rect_yellow_border"
android:ems="10"
android:hint="Enter Game PIN"
android:inputType="text"
android:textAlignment="center"
android:textColor="@color/colorPrimary"
android:textColorHint="#40292929"
app:layout_constraintBottom_toBottomOf="parent"
app:layout_constraintEnd_toEndOf="parent"
app:layout_constraintHorizontal_bias="0.503"
app:layout_constraintStart_toStartOf="parent"
app:layout_constraintTop_toBottomOf="@+id/products_toolbar"
app:layout_constraintVertical_bias="0.309" />
我也尝试在Java
中设置背景,但是当我尝试这样做时,该问题也未解决。有帮助吗?
这是我的drawable
文件。这有点不必要,很奇怪,因为我只是编辑了一个圆角形状的代码并将其变成正方形
<?xml version="1.0" encoding="utf-8"?>
<selector xmlns:android="http://schemas.android.com/apk/res/android" >
<item android:state_pressed="true" >
<shape android:shape="rectangle" >
<stroke android:width="3dip" android:color="#ffc847" />
<gradient android:angle="-180" android:startColor="#ffffff" android:endColor="#ffffff" />
</shape>
</item>
<item android:state_focused="true">
<shape android:shape="rectangle" >
</shape>
</item>
<item >
<shape android:shape="rectangle" >
<stroke android:width="3dip" android:color="#ffc847" />
<stroke android:width="3dip" android:color="#ffc847" />
<solid android:color="#ffc847"/>
<gradient android:angle="-45" android:startColor="#ffffff" android:endColor="#ffffff" />
</shape>
</item>
</selector>
在我的Activity
中,定义EditText
所做的全部是这样:
@Override
protected void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.activity_private_room_lobby);
final Button createPrivateGame = findViewById(R.id.createPrivateGame);
final Button joinPrivateRoom = findViewById(R.id.joinPrivateGame);
final EditText pinEntry = findViewById(R.id.enterCode);
joinPrivateRoom.setOnClickListener(new View.OnClickListener() {
@Override
public void onClick(View v) {
String pin = pinEntry.getText().toString().trim();
if(TextUtils.isEmpty(pin) || pin.length() > 6 || pin.length() < 6)
{
Toast.makeText(PrivateRoomLobby.this, "Please enter a 6 digit PIN to enter the room", Toast.LENGTH_LONG).show();
} else {
joinGame(pin);
}
}
});
答案 0 :(得分:1)
选择器用于通过其各种状态定义view
组件的背景颜色或背景图像。有关更多详细信息,请检查this
您只需要使用shape
<?xml version="1.0" encoding="utf-8"?>
<shape xmlns:android="http://schemas.android.com/apk/res/android" >
<stroke android:width="3dip" android:color="#ffc847" />
<solid android:color="#ffffff"/>
<!-- <gradient android:angle="-45" android:startColor="#ffffff" android:endColor="#ffffff" />-->
</shape>