Question

我的方法$ _POST在其他形式下也可以正常工作，但在这里我的$ _POST无法正常工作。这是我的表格

<h3 class="page-title">Medicine Inventory: Add Stock</h3>
      <form method="POST" action="PHP/action_insertaddstock.php" accept-charset="UTF-8">

        <div class="panel panel-default">
          <div class="panel-heading">

          </div>

          <div class="panel-body">
            <div class="row">
              <div class="col-xs-12 form-group">
                <label for="medicine_id" class="control-label">Medicine ID (Required) :</label>
                <select class="form-control select2" required="" id="medicine_id" name="medicine_id">
                  <option value="" selected="selected">-- Please select --</option>
                   <?php foreach($medicines as $val) : ?>
                  <option value="<?php echo $val['id']; ?>"><?php echo $val['name']; ?></option>
                  <?php endforeach; ?>
                </select>
                <p class="help-block"></p>
              </div>
            </div>
            <div class="row">
              <div class="col-xs-12 form-group">
                <label for="qty" class="control-label">Quantity (Required) :</label>
                <input class="form-control" placeholder="" required="" name="qty" type="number" id="qty">
                <p class="help-block"></p>
              </div>
            </div>
            <div class="row">
              <div class="col-xs-12 form-group">
                <label for="xdate" class="control-label">Expiry Date (Required) :</label>
                <input class="form-control " placeholder="" required="" name="xdate" id="xdate">
                <p class="help-block"></p>

              </div>
            </div>

          </div>
        </div>

        <button class="btn btn-success" type="submit" name="submit" >Save</button>
      </form>

我的动作在这里

<?php

if (isset($_POST['submit'])) {

include_once('CONFIG/config.php');
include_once('CONFIG/db.php');

$Med_id =  $_POST['medicine_id'];
$Qty = $_POST['qty'];
$Xdate =  $_POST['xdate'];
$Timestamp = date("Y-m-d H:i:s");




if(empty($Med_id) || empty($Qty) || empty($Xdate) || empty($Timestamp)){
      header("Location: ../added_stock.php?add=empty");
     exit();    
 }else{

            $sql = "INSERT INTO medicines_addeds (qty, xdate, created_at, 
 med_id) VALUES ('$Qty', '$Xdate', '$Timestamp', '$Med_id')";
            mysqli_query($conn, $sql);
            header("Location: ../added_stock.php?add=success");
            exit();


}

} else {
 header("Location: ../MIAdd_medicine.php");
 exit();
}

查询工作正常，因为我尝试将值放入变量中，并将其插入到数据库中，但是当我尝试$ _POST时，它什么也无法成功运行，但是我的数据库为空。请帮助我

表结构在这里

1   idPrimary   int(11)             No  None        AUTO_INCREMENT   
2   qty int(11)                     Yes NULL             
3   xdate   date                    Yes NULL             
4   created_at  timestamp           Yes NULL            
5   edited_at   timestamp           Yes NULL             
6   deleted_at  timestamp           Yes NULL            
7   med_id  int(11)                 Yes NULL

Answer 1

使用xp解析您的xdate

 state = this.createAppState({
        take: 10,
        group: []
    });

为什么我的发布方法无法正常工作

1 个答案: