Question

我有一个基本表，希望从中解析一些数据。

现在我运行两个查询以获取所需的数据。

查询1（用于获取总数或tally_id的“数量”）

PartyEvent

在上面的示例中，我得到的结果是247

查询2

export class EventUtility {
    // pick item based on JSON-friendly conditional notation
    events: Array<PartyEvent | AppointmentEvent | MealEvent>

    constructor(events: Array<PartyEvent | AppointmentEvent | MealEvent>) {
        this.events = events;
    }

    earliestEvent(): PartyEvent | AppointmentEvent | MealEvent {
        // determine earliest event in array and return it
        return event;
    }
}

这给了我每个'tally_id'的总数，例如

SELECT
 count(*)
FROM
 tally
WHERE
time >= '2019-02-25 00:00' AND time <= '2019-03-04 21:00';

是否有一种将两者结合在一起的方法，所以这是一个很好的无缝查询操作？我想查看块的总数，如上面的247所示，以及每种单独类型的块的总数。

感谢interwebz！

Answer 1

使用SELECT tally_id,count(*) FROM tally WHERE time >= '2019-02-25 00:00' AND time <= '2019-03-04 21:00' GROUP BY tally_id union SELECT 'total', count(*) FROM tally WHERE time >= '2019-02-25 00:00' AND time <= '2019-03-04 21:00'组合两个查询

    protected override void ApplyAbpConceptsForAddedEntity(EntityEntry entry, long? userId, EntityChangeReport changeReport)
    {
        CheckAndSetMustHaveUserIdProperty(entry.Entity, userId);
        base.ApplyAbpConceptsForAddedEntity(entry, userId, changeReport);
    }

    private void CheckAndSetMustHaveUserIdProperty(object entryEntity, long? userId)
    {
        if (userId == null)
            return;


        if (!(entryEntity is IMustHaveUser))
        {
            return;
        }

        var entity = entryEntity.As<IMustHaveUser>();


        entity.UserId = userId.Value;
    }

SQLITE3查询COUNT和ORDER BY

1 个答案: